Last visit was: 24 Apr 2026, 07:04 It is currently 24 Apr 2026, 07:04
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
brokerbevo
Joined: 11 Apr 2008
Last visit: 14 Jan 2009
Posts: 47
Own Kudos:
Location: Chicago
Posts: 47
Kudos: 238
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
zonk
User avatar
Current Student
Joined: 12 Jul 2008
Last visit: 10 Nov 2013
Posts: 366
Own Kudos:
Concentration: Finance, Entrepreneurship, Health Care
Schools:Wharton
Posts: 366
Kudos: 354
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
brokerbevo
Joined: 11 Apr 2008
Last visit: 14 Jan 2009
Posts: 47
Own Kudos:
Location: Chicago
Posts: 47
Kudos: 238
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
GMAT TIGER
Joined: 29 Aug 2007
Last visit: 17 Aug 2011
Posts: 1,012
Own Kudos:
Given Kudos: 19
Posts: 1,012
Kudos: 1,796
Kudos
Add Kudos
Bookmarks
Bookmark this Post
brokerbevo
I'm having trouble with the rule behind this concept. This problem is a good example of my confusion:

If y is an integer, is y divisible by 3?
(1) y = 2x^3 + 9x^2 - 5x
(2) x is indivisible by 3

Please explain your rationale behind your answer.

Here is what I did:

(1) factor out an x --> x (2x^2 + 9x - 5)
factor the quadratic --> x (2x - 1) (x + 5)
so, y is the product of 3 integers and I wrote down that since 3 integers are multiplied together, it must be that it is divisible by 3. HOWEVER, I thought that this rule ONLY applies if the integers that are multiplied together are consecutive!!!

For example, x (x - 1) (x -4) is not divisible by 3 (even though it is the product of 3 numbers) because the parts are not consecutive.

Please explain...

you are almost there.

(1) y = 2x^3 + 9x^2 - 5x = x (2x^2 + 9x - 5) = x (2x - 1) (x + 5)

plug-in: any integer value for x in the above expression is divisible by 3.
if x = 2: x (2x - 1) (x + 5) = 2 (2x2 - 1) (2+5) = 2 x 3 x 7. suff.
if x = 4: x (2x - 1) (x + 5) = 4 (2x4 - 1) (4+5) = 4 x 7 x 9. suff.
if x = 5: x (2x - 1) (x + 5) = 5 (2x5 - 1) (5+5) = 4 x 9 x 10. suff.
if x = 7: x (2x - 1) (x + 5) = 7 (2x7 - 1) (7+5) = 7 x 13 x 12. suff.

i believe every integer value for x result y divisible by 3.

2: x = 3k is not sufficient.

So //A//
User avatar
IanStewart
User avatar
GMAT Tutor
Joined: 24 Jun 2008
Last visit: 24 Apr 2026
Posts: 4,143
Own Kudos:
Given Kudos: 99
Expert
Expert reply
Posts: 4,143
Kudos: 11,277
Kudos
Add Kudos
Bookmarks
Bookmark this Post
brokerbevo
I'm having trouble with the rule behind this concept. This problem is a good example of my confusion:

If y is an integer, is y divisible by 3?
(1) y = 2x^3 + 9x^2 - 5x
(2) x is indivisible by 3

Please explain your rationale behind your answer.

Here is what I did:

(1) factor out an x --> x (2x^2 + 9x - 5)
factor the quadratic --> x (2x - 1) (x + 5)
so, y is the product of 3 integers and I wrote down that since 3 integers are multiplied together, it must be that it is divisible by 3. HOWEVER, I thought that this rule ONLY applies if the integers that are multiplied together are consecutive!!!

For example, x (x - 1) (x -4) is not divisible by 3 (even though it is the product of 3 numbers) because the parts are not consecutive.

Please explain...

Well, it doesn't *only* apply when the integers are consecutive. Say x is an integer. You know already that one of x, x+1 or x+2 is a multiple of 3. Well, that guarantees that one of, say, x, x+4, and x+8 is divisible by 3 (because if x+1 is, then x+1+3 = x+4 is, and if x+2 is, so is x+2 + 6 = x+8), and many other combinations besides.

You can apply that logic here if you want. We know that one of these numbers: x, x+1 or x+2 is a multiple of 3:

-If x is a multiple of 3, then x is a multiple of 3
-If x+1 is a multiple of 3, then 2x+2 is also a multiple of 3, and (subtract 3) 2x-1 is also a multiple of 3
-If x+2 is a multiple of 3, then x+2+3 = x+5 is also a multiple of 3.

So one of x, 2x-1 or x+5 will always be a multiple of 3, and since y = x (2x - 1) (x + 5), y must be a multiple of 3.

There are other ways to go about the question that might be preferable here (modular arithmetic, for example); I just wanted to show how you can extend the logic about 'consecutive numbers' to this situation.
User avatar
scthakur
Joined: 17 Jun 2008
Last visit: 30 Jul 2009
Posts: 608
Own Kudos:
Posts: 608
Kudos: 453
Kudos
Add Kudos
Bookmarks
Bookmark this Post
But, the question stem does not specifically mention that x is an integer....hence I will go with C.
User avatar
GMAT TIGER
Joined: 29 Aug 2007
Last visit: 17 Aug 2011
Posts: 1,012
Own Kudos:
Given Kudos: 19
Posts: 1,012
Kudos: 1,796
Kudos
Add Kudos
Bookmarks
Bookmark this Post
scthakur
But, the question stem does not specifically mention that x is an integer....hence I will go with C.

Do you have any non-integer value for x that yeilds an integer value for y?


any example?
User avatar
amitdgr
Joined: 30 Jun 2008
Last visit: 21 May 2013
Posts: 534
Own Kudos:
Given Kudos: 1
Posts: 534
Kudos: 3,212
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMAT TIGER
brokerbevo
I'm having trouble with the rule behind this concept. This problem is a good example of my confusion:

If y is an integer, is y divisible by 3?
(1) y = 2x^3 + 9x^2 - 5x
(2) x is indivisible by 3

Please explain your rationale behind your answer.

Here is what I did:

(1) factor out an x --> x (2x^2 + 9x - 5)
factor the quadratic --> x (2x - 1) (x + 5)
so, y is the product of 3 integers and I wrote down that since 3 integers are multiplied together, it must be that it is divisible by 3. HOWEVER, I thought that this rule ONLY applies if the integers that are multiplied together are consecutive!!!

For example, x (x - 1) (x -4) is not divisible by 3 (even though it is the product of 3 numbers) because the parts are not consecutive.

Please explain...

you are almost there.

(1) y = 2x^3 + 9x^2 - 5x = x (2x^2 + 9x - 5) = x (2x - 1) (x + 5)

plug-in: any integer value for x in the above expression is divisible by 3.
if x = 2: x (2x - 1) (x + 5) = 2 (2x2 - 1) (2+5) = 2 x 3 x 7. suff.
if x = 4: x (2x - 1) (x + 5) = 4 (2x4 - 1) (4+5) = 4 x 7 x 9. suff.
if x = 5: x (2x - 1) (x + 5) = 5 (2x5 - 1) (5+5) = 4 x 9 x 10. suff.
if x = 7: x (2x - 1) (x + 5) = 7 (2x7 - 1) (7+5) = 7 x 13 x 12. suff.

i believe every integer value for x result y divisible by 3.

2: x = 3k is not sufficient.

So //A//


GMAT TIGER, why are we trying only integer values of x here ? The stem does not mention anything about x, it could be a fraction also.
User avatar
amitdgr
Joined: 30 Jun 2008
Last visit: 21 May 2013
Posts: 534
Own Kudos:
Given Kudos: 1
Posts: 534
Kudos: 3,212
Kudos
Add Kudos
Bookmarks
Bookmark this Post
IanStewart


-If x is a multiple of 3, then x is a multiple of 3
-If x+1 is a multiple of 3, then 2x+2 is also a multiple of 3, and (subtract 3) 2x-1 is also a multiple of 3
-If x+2 is a multiple of 3, then x+2+3 = x+5 is also a multiple of 3.

So one of x, 2x-1 or x+5 will always be a multiple of 3, and since y = x (2x - 1) (x + 5), y must be a multiple of 3.

There are other ways to go about the question that might be preferable here (modular arithmetic, for example); I just wanted to show how you can extend the logic about 'consecutive numbers' to this situation.


If x is a multiple of 3, then x is a multiple of 3 . I guess there is a typo or am I missing the concept ?

Ian how do we apply modular arithmetic here ? Please guide.

Thanks
User avatar
IanStewart
User avatar
GMAT Tutor
Joined: 24 Jun 2008
Last visit: 24 Apr 2026
Posts: 4,143
Own Kudos:
Given Kudos: 99
Expert
Expert reply
Posts: 4,143
Kudos: 11,277
Kudos
Add Kudos
Bookmarks
Bookmark this Post
amitdgr


If x is a multiple of 3, then x is a multiple of 3 . I guess there is a typo or am I missing the concept ?


No typo- I was just pointing out that one of x, x+5 or 2x-1 must be a multiple of 3, and if x is a multiple of 3, then it's just obvious that one of the three expressions is a multiple of 3.

I can explain how to approach this with modular arithmetic, but be aware that you won't need modular arithmetic on the GMAT. It would take me too long to explain the theory, so if you don't know modular arithmetic already, don't worry about it!

We want to know if

2x^3 + 9x^2 - 5x ~ 0 (mod 3)

We don't need to bother simplifying, but it makes things slightly easier: since 9 ~ 0 mod 3, and -5 ~ 1 mod 3, we just want to know if:

2x^3 + x ~ 0 (mod 3)

Now it's easy to check that if x ~ 0, 1 or 2 (mod 3), that 2x^3 + x is always congruent to 0 (mod 3), so it must be divisible by 3.
User avatar
IanStewart
User avatar
GMAT Tutor
Joined: 24 Jun 2008
Last visit: 24 Apr 2026
Posts: 4,143
Own Kudos:
Given Kudos: 99
Expert
Expert reply
Posts: 4,143
Kudos: 11,277
Kudos
Add Kudos
Bookmarks
Bookmark this Post
GMAT TIGER
scthakur
But, the question stem does not specifically mention that x is an integer....hence I will go with C.

Do you have any non-integer value for x that yeilds an integer value for y?


any example?

y = 2x^3 + 9x^2 - 5x is a continuous function with an unrestricted range, so y can take on any value at all (graph it on the co-ordinate plane and you'll see why). I've ignored the possibility, in my posts above, that x is not an integer, because on the GMAT you would never see a question like this unless you were told in the question that x is an integer. I assumed there was a typo in the question, and that it was meant to begin "If x is an integer" rather than "If y is an integer". If the question doesn't mention this, it's really testing whether you know properties of continuous functions, something you learn in calculus, not in GMAT prep.

Still, if we accept the possibility that x is not an integer, the answer is not C, since Statement 2 is not at all helpful in this case; the answer would be E. But I'm sure the intended answer is A, and that the question intends for x to be an integer.



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!