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albany09
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A certain list consists of 21 different numbers. If n is in 05 Oct 2008, 16:51
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A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?

A. 1/20
B. 1/6

C. 1/5
D. 4/21 :?
E. 5/21 :



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lylya4
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A certain list consists of 21 different numbers. If n is in 05 Oct 2008, 20:51
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I go for C

Mean = n/4
=> Sum = 20*n/4 = 5n

Ratio = n / (5n) = 1/5
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scthakur
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A certain list consists of 21 different numbers. If n is in 06 Oct 2008, 00:12
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B for me.

If x is the mean of the remaining 20 numbers than n = 4x.

Sum of all the 21 numbers = 20x + n = 24x

Hence, the ratio = 4x/24x = 1/6.
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yezz
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A certain list consists of 21 different numbers. If n is in 06 Oct 2008, 03:08
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albany09
A certain list consists of 21 different numbers. If n is in the list and n is 4 times the average (arithmetic mean) of the other 20 numbers in the list, then n is what fraction of the sum of the 21 numbers in the list?

A. 1/20
B. 1/6

C. 1/5
D. 4/21
E. 5/21 :
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sum of 20 = x , sum of 21 = x+n

n = x/5 , sum of 21 = x+x/5 = (5x+x)/5 = 6x/5

(x/5)/ 6x/5 = 1/6



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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