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10 Jun 2004, 22:02
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This question was in PP1
Is X divided by 36?
(1) X is divisible by 12
(2) X is divisible for 9
What is the best way to approach divisibility questions? Picking out numbers in this case did not help me...
Is X divided by 36?
(1) X is divisible by 12
(2) X is divisible for 9
What is the best way to approach divisibility questions? Picking out numbers in this case did not help me...
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10 Jun 2004, 22:35
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easy C.
Divisible by 12 does not guarantee division by 36.Same case with 9.A&B ruled out.
How ever together you get factors (3,4,9) and you can get 36 from (9*4) so it is divisible by 36.
Divisible by 12 does not guarantee division by 36.Same case with 9.A&B ruled out.
How ever together you get factors (3,4,9) and you can get 36 from (9*4) so it is divisible by 36.
10 Jun 2004, 23:49
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The approach I follow:
* Break down the given number into its prime factors; 36 = 2^2 * 3^2
* So any given number should have at least this combination of prime
factors
Now looking at the statements:
(1) Any number divisible by 12 contains the following combo- 2^2 *3 : a
3 is missing so this stmt is not enough.
(2) Any number divisible by 9 contains the following combo- 3^2: 2^2 is
missing so this stmt is not enough.
Combining both we get 2^2 and 3^2, hence (C).
Hope this helps
* Break down the given number into its prime factors; 36 = 2^2 * 3^2
* So any given number should have at least this combination of prime
factors
Now looking at the statements:
(1) Any number divisible by 12 contains the following combo- 2^2 *3 : a
3 is missing so this stmt is not enough.
(2) Any number divisible by 9 contains the following combo- 3^2: 2^2 is
missing so this stmt is not enough.
Combining both we get 2^2 and 3^2, hence (C).
Hope this helps
