The answer is 5/8. D.
Here's how:
Total number of ways that you can have a product
n(n+1)(n+2) out of the integers 1 thru 96 = 96.
If you have an even integer as
n, then
n+2 will also be an even integer. For all of these cases, with
n as an even integer, the product is divisible by 8. This accounts for half the total possibilities: 48. Examples:
2,3,4 divisible; 4,5,6 divisible; 6,7,8 divisible; and so on.
For the cases where
n is an odd integer,
n+2 must also be an odd integer. Product of two odd integers is another odd integer, which is not divisible by 8. Our only redemption here will be the cases where we have a multiple of 8 as the middle integer (
n+1). This can only happen 12 times between integers 1 and 96.
Thus, our total divisibility cases = 48 + 12 = 60
Required probability = 60/96 = 5/8.
PS. Nice question!