Bunuel
If x, y and are non zero numbers, what is the value of \(\frac{x}{y}+\frac{z}{y}\)?
(1) \((3x - 2y)^2= 0\)
(2) \(3x = 2y = 4z\)
Target question: What is the value of \(\frac{x}{y}+\frac{z}{y}\)? Statement 1: \((3x - 2y)^2= 0\) Since we have no information about the value of z, we can't answer the
target question with certainty.
Statement 1 is NOT SUFFICIENT
Statement 2: \(3x = 2y = 4z\)Take \(3x = 2y\) and divide both sides by \(3\) to get: \(x = \frac{2y}{3}\)
Take \(4z = 2y\) and divide both sides by \(4\) to get: \(z = \frac{2y}{4}= \frac{y}{2}\)
At this point, we COULD replace \(x\) and \(z\) with \(\frac{2y}{3}\) and \(\frac{y}{2}\) respectively, in which case we get an expression with y's only, in which case the y's cancel out to give us an actual value.
In other words, we COULD answer the target question, which means statement 2 is SUFFICIENT
Answer: B
Not convinced?
\(\frac{x}{y}+\frac{z}{y}\)\(=\frac{\frac{2y}{3}}{y}+ \frac{\frac{y}{2}}{y}= \frac{2}{3}+\frac{1}{2}\)
\(=\frac{7}{6}\)