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21 Jan 2026, 17:48
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
49% (02:52) correct
51%
(02:59)
wrong
based on 65
sessions
History
Date
Time
Result
Not Attempted Yet
In a viva-voce examination, some students were asked four questions. As much percentage of candidates answered all the questions correctly as another percentage of candidates that answered no question correctly. No more than half of the candidates answered one question correctly.
How does the number of candidates who answered three questions correctly compare to the number of candidates who answered none of the questions correctly?
(1) Half as many candidates answered two questions correctly as those who answered one question correctly.
(2) Half as many candidates answered three questions correctly as those who answered two questions correctly.
How does the number of candidates who answered three questions correctly compare to the number of candidates who answered none of the questions correctly?
(1) Half as many candidates answered two questions correctly as those who answered one question correctly.
(2) Half as many candidates answered three questions correctly as those who answered two questions correctly.
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28 Jan 2026, 09:43
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Amity007
Let the # of candidates be \(100\)
Let \(10\%\) get all correct.
Let \(10\%\) get all wrong.
Those who get only one correct cannot be more than \(50.\)
(1) Half as many candidates answered two questions correctly as those who answered one question correctly.
\(1\) correct \(= 20\)
\(2\) correct \(= 10\)
\(3\) correct \(= 50\)
\(1\) correct \( = 40\)
\(2\) correct \( = 20\)
\(3\) correct \( = 20\)
etc.
INSUFF.
(2) Half as many candidates answered three questions correctly as those who answered two questions correctly.
\(1\) correct \(= y\)
\(2\) correct \(= x\)
\(3\) correct = \( \frac{x}{2}\)
\( \frac{3x}{2}+20+y =100 \).Where \(y\) cannot exceed \(50\)
\( \frac{3x}{2}+y = 80 \)
\(y \) can be \(5,20, \), etc.
Hence \(x\) can be \(50,40, ..\) , hence \( \frac{x}{2}\) \(= 25 , 20, \) etc
\((10+10+50+25+5=100 ), (10+10+40+20+20 = 100)\) etc.
INSUFF.
1+2
\( {x}+\frac{x}{2}+ \frac{x}{4}+ 20 = 100\)
We can certainly solve for \( x\)
SUFF.
Ans C
Hope it helped.
03 Feb 2026, 05:21
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The answer is incorrect because we do not know the exact value of all those who got exactly 1 answer correct.
