If p and q are consecutive even integers, is pq? 1) p-2

Question

If p and q are consecutive even integers, is p>q?

1) p-2 and q+2 are consecutive even integers
2) p is prime

vidyasagar · Answer

a) True only for p p-2=-2 & q+2=0 (Cons. Even) implies p>q for all .SUFF b) P=PRIME and EVEN=2 implies q = 4. i.e. p

dahcrap · Answer

I think it is B. I shall explain further if I am right

grad_mba · Answer

go with (A)

given p and q are consecutive even integers.

St1 : (p-2) and (q+2) are consecutive even integers

now if we assume p>q,

p-2 = q + 2 +2 => p = q + 6 ; but if p = q +6, p and q cannot be consecutive even

if we assume p<q> p = q+2 --- SUFF 


St2 : p is prime => p = 2 , q can be either '0' or '4' INSUFF

Hence (A)

Andr359 · Answer

(1) if p-2 and q+2 are consecutive also, then it MUST be the case that p>q. Suff.

(2) p is prime, then it´s =2. If p and q are consecutive even integers, then q = 0 or 4 (even integer can be +ve, -ve, or 0), then we cannot know for sure whether p<>q. Insuff.

A.

ankita · Answer

I'll go with A.

1) P-2 and q+2 are consecutive even integers.
 take the sample numbers where both numbers are positive and both are negative. you will see that p>q is always true for p-2 and q +2 to be consecutive even integers. you can also test this eith {-2, 0} and {0, 2}. - sufficient

2) p is prime. q could be 0 or 4. for 0 p >q holds up but not for 4. - not sufficient

Ankita

michaelny2001 · Answer

Hey guys,
when i first looked at it, it also thought it was A, but if yo uthink about it's not enough to just say that p IS greater the q. In this case q is greater than p. (from the second option, where p is prime) The question asks if p>q, in this case you could you with certainty that it is not, therefore D, wither statement is suffiecient. One proves that p>q, and the other that P<q. Who cares if it is or not, point is that you could say it with certinty, and this is what GMAT wants.

GMATBLACKBELT · Answer

Stmnt1:

p=6 q=4

6-2=4, 4+2=6 in this case p is greater than q. 6>4. You gotta take what you plugged in for p and q. Not the result of the subtraction.



B is insuff. While P has to be 2.

Q could be 0 or 4 since 0 is considered an even integer.


Answer A

Mishari · Answer

For this DS question, I will examine each statement alone.

 What's asked:  is p>q ?
 What's given:  p and q are consecutive even integers

What do we know?
either p = q+2 or p = q-2

1) p-2 and q+2 are consecutive even integers 
-------------------------------------------------------
if p = q-2, then p-2 = q-4 which can never be a consecutive even integer after or before q+2
Thus, p = q+2 and hence p>q

 Statement 1 is sufficient 

2) p is prime
----------------
We know that p is even, and the only even prime integer is 2. Since q and p are consecutive even integers, q can be either 0 or 4.

 Statement 2 is insufficient 


 My Answer:   A

Caas · Answer

OA is A

Thank you all!

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If p and q are consecutive even integers, is p>q? 1) p-2

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