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KillerSquirrel
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a,b and c are positive integers and b < a Is a^2/b^2 = c 23 Nov 2007, 13:23
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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100% (03:57) correct 0% (00:00) wrong based on 1 sessions

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a,b and c are positive integers and b sqrt(a)

Have fun - OA soon

:)



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walker
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a,b and c are positive integers and b < a Is a^2/b^2 = c 23 Nov 2007, 14:02
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A.

1. a^2/b^2 = 1. k^2 (where k - integer) or 2. fraction

therefore, neither fraction nor k^2 can not be prime. suff

2. any c. insuff.
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a,b and c are positive integers and b < a Is a^2/b^2 = c 23 Nov 2007, 19:50
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walker
A.

1. a^2/b^2 = 1. k^2 (where k - integer) or 2. fraction

therefore, neither fraction nor k^2 can not be prime. suff

2. any c. insuff.
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Walker dint understand your answer...could you please explain?
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a,b and c are positive integers and b < a Is a^2/b^2 = c 23 Nov 2007, 22:13
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the OA is (A)

:)
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walker
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a,b and c are positive integers and b < a Is a^2/b^2 = c 23 Nov 2007, 22:22
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spider
Walker dint understand your answer...could you please explain?
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1. n=a^2/b^2

there are two cases:
a) n-integer
In this case n must be equal k^2 where k - integer. n is not prime. For example. a=5*3*7*2*13, b=5*3*2*13 ==> n=7^2
b) n-fraction ==> n is not also prime
suff



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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