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young_gun
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Is |x| < 1? (1) |x+1| = 2|x-1| (2) |x-3| 0 09 Apr 2008, 16:50
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Is |x| < 1?

(1) |x+1| = 2|x-1|
(2) |x-3| ≠ 0



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Is |x| < 1? (1) |x+1| = 2|x-1| (2) |x-3| 0 09 Apr 2008, 16:56
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young_gun
Is |x| < 1?

(1) |x+1| = 2|x-1|
(2) |x-3| ≠ 0
Show more

C.

(1) |x+1| = 2*|x-1|
x = 3 or x=1/3
INSUFFICIENT

(2) x ≠ 3
INSUFFICIENT

Together, x=1/3
SUFFICIENT
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Is |x| < 1? (1) |x+1| = 2|x-1| (2) |x-3| 0 09 Apr 2008, 16:58
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bkk145
young_gun
Is |x| < 1?

(1) |x+1| = 2|x-1|
(2) |x-3| ≠ 0

C.

(1) |x+1| = 2*|x-1|
x = 3 or x=1/3
INSUFFICIENT

(2) x ≠ 3
INSUFFICIENT

Together, x=1/3
SUFFICIENT
Show more

bkk, do you think you could show me how in (1) you solved x=3 or x=1/3? I'm not too great with abs values. Thanks!
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Is |x| < 1? (1) |x+1| = 2|x-1| (2) |x-3| 0 09 Apr 2008, 17:05
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C...

1) says x can be 3 or 1/3

3) says x cant be 3..or -3 we dont know..

together..yes..

x=1/3
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Is |x| < 1? (1) |x+1| = 2|x-1| (2) |x-3| 0 09 Apr 2008, 17:08
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fresinha12
C...

1) says x can be 3 or 1/3

3) says x cant be 3..or -3 we dont know..

together..yes..

x=1/3
Show more

can you explain how you got the bold? thx
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Is |x| < 1? (1) |x+1| = 2|x-1| (2) |x-3| 0 09 Apr 2008, 17:11
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bkk145
young_gun
Is |x| < 1?

(1) |x+1| = 2|x-1|
(2) |x-3| ≠ 0

C.

(1) |x+1| = 2*|x-1|
x = 3 or x=1/3
INSUFFICIENT

(2) x ≠ 3
INSUFFICIENT

Together, x=1/3
SUFFICIENT

bkk, do you think you could show me how in (1) you solved x=3 or x=1/3? I'm not too great with abs values. Thanks!
Show more

Sure, you have
|x+1| = 2*|x-1|
You know that
|x+1| is positive when x>-1 and negative when x<-1
|x-1| is positive when x>1 and negative when x<1
This means that in a number line, the intervals you have are:
x<-1, -1<x<1, x>1

Now, solve the equation according to those intervals:
For x<-1,
-x-1 = 2*(-x+1)
-x-1 = -2x+2
x = 3

For -1<x<1,
x+1 = 2*(-x+1)
x+1 = -2x+2
x = 1/3

For x>1
x+1 = 2*(x-1)
x+1 = 2x-2
x = 3

x equals to 3 or 1/3

I know, all these signs are confusing! I attached a document for you, take a look. It helped me.
Attachments

3529-760-q50-v-44-absolute-value-inequality.doc [73.5 KiB]
Downloaded 156 times

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Is |x| < 1? (1) |x+1| = 2|x-1| (2) |x-3| 0 09 Apr 2008, 17:20
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young_gun
Is |x| < 1?
(1) |x+1| = 2|x-1|
(2) |x-3| ≠ 0
Show more

1: |x+1| = 2|x-1|
if x is +ve:
x + 1 = 2x - 2
x = 3

if x is -ve:
x + 1 = -2x + 2
x = 1/3

so insufff.

2: if (x-3) is not equal to 0, then x is not 3 but do not know whether x is > than or < 3. NSF

1 & 2: x = 1/3. suff.

C.
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Is |x| < 1? (1) |x+1| = 2|x-1| (2) |x-3| 0 11 Apr 2008, 00:53
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bkk145.

Kudos for the doc

Thanks all for clarifications.



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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