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19 Jun 2008, 05:02
Kudos
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N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Can u please tell me how to solve this
Archived Topic
Hi there,
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19 Jun 2008, 05:54
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vdhawan1
Is the answer E,?
IS this a GMAT question?
Hi, vdhawan1,
I have A for this one. Here's my reasoning:
Let’s rewrite our series like this:
t1 t3 t5 …
t2 t4 t6 …
and this is, according to the given formula, can be written as
t1 t1+11 t1+2*11 … t1+11*n
t2 t2+11 t2+2*11 … t2+11*n
So, it becomes clear that we in fact have two arithmetic series here, mixed with each other. For both series, d=11.
Now let’s analyze the statements.
(statement 1): First, let’s check if 633 can be represented as 39+11*n, where n is an integer. Yes, it’s possible, 633=11*54+39. So, 633 is in the series, and 1) is sufficient.
(statement 2): Check if 633 can be represented as 43+11*n – this time, it can’t be. Thus, 633 is not one of t2, t4, t6, … and we have no info regarding if it is in t1, t3, t5, … subseries. Hence, 2) is insufficient.
Therefore, the answer is A.
I have A for this one. Here's my reasoning:
Let’s rewrite our series like this:
t1 t3 t5 …
t2 t4 t6 …
and this is, according to the given formula, can be written as
t1 t1+11 t1+2*11 … t1+11*n
t2 t2+11 t2+2*11 … t2+11*n
So, it becomes clear that we in fact have two arithmetic series here, mixed with each other. For both series, d=11.
Now let’s analyze the statements.
(statement 1): First, let’s check if 633 can be represented as 39+11*n, where n is an integer. Yes, it’s possible, 633=11*54+39. So, 633 is in the series, and 1) is sufficient.
(statement 2): Check if 633 can be represented as 43+11*n – this time, it can’t be. Thus, 633 is not one of t2, t4, t6, … and we have no info regarding if it is in t1, t3, t5, … subseries. Hence, 2) is insufficient.
Therefore, the answer is A.
