Last visit was: 22 Apr 2026, 07:24 It is currently 22 Apr 2026, 07:24
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
AnkitK
Joined: 11 Feb 2011
Last visit: 01 Dec 2012
Posts: 82
Own Kudos:
1,383
 [2]
Given Kudos: 21
Posts: 82
Kudos: 1,383
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
jamifahad
Joined: 03 Mar 2010
Last visit: 14 Mar 2015
Posts: 256
Own Kudos:
Given Kudos: 22
Posts: 256
Kudos: 1,734
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
AnkitK
Joined: 11 Feb 2011
Last visit: 01 Dec 2012
Posts: 82
Own Kudos:
Given Kudos: 21
Posts: 82
Kudos: 1,383
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
AnkitK
Joined: 11 Feb 2011
Last visit: 01 Dec 2012
Posts: 82
Own Kudos:
Given Kudos: 21
Posts: 82
Kudos: 1,383
Kudos
Add Kudos
Bookmarks
Bookmark this Post
@Jamifahad:ok i got it .Sorry for that silly question there .OA is A .
User avatar
sudhir18n
User avatar
Current Student
Joined: 26 May 2005
Last visit: 13 Feb 2013
Posts: 351
Own Kudos:
Given Kudos: 13
Posts: 351
Kudos: 616
Kudos
Add Kudos
Bookmarks
Bookmark this Post
AnkitK
8 k 8
k 8 8
_______
16p6

if k and p represent non zero digits within the integers above,what is p ?

A.6
B.7
C.8
D.9
E.17

looking at the question we know we are adding as units digit is 6(8+8), so 1 is carried over to next number
thus we know
9( 8 + 1 carried over) +K = p
9+k = 16
k = 7
hence P = 6= A
User avatar
KarishmaB
Joined: 16 Oct 2010
Last visit: 21 Apr 2026
Posts: 16,439
Own Kudos:
79,384
 [2]
Given Kudos: 484
Location: Pune, India
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 16,439
Kudos: 79,384
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
AnkitK
8 k 8
k 8 8
_______
16p6

if k and p represent non zero digits within the integers above,what is p ?

A.6
B.7
C.8
D.9
E.17

The question is quite straight forward. Look at the big picture first. Eight hundred something gets added to (the addition sign is missing here) another 3 digit number to give you sixteen hundred something.
This means the second number should be either seven hundred something or eight hundred something. So k is either 7 or 8.
If you put k = 7, you get 878 + 788 = 1666. So you get p = 6.
k cannot be 8 because 888 + 888 gives you seventeen hundred something.
User avatar
gsaxena26
Joined: 15 Nov 2009
Last visit: 31 Aug 2011
Posts: 27
Own Kudos:
Given Kudos: 2
Posts: 27
Kudos: 179
Kudos
Add Kudos
Bookmarks
Bookmark this Post
8k8
+k88
-------
1,6p6
-------

If k and p represent non-zero digits within the integers above, what is p?

1. 6
2. 7
3. 8
4. 9
5. 17

What's the logic behind this to solve these problems? Can someone please explain? I struggle badly on these and they seem to appear on the real GMAT.
User avatar
gsaxena26
Joined: 15 Nov 2009
Last visit: 31 Aug 2011
Posts: 27
Own Kudos:
Given Kudos: 2
Posts: 27
Kudos: 179
Kudos
Add Kudos
Bookmarks
Bookmark this Post
8k8
+k88
-------
1,6p6
-------

If k and p represent non-zero digits within the integers above, what is p?

1. 6
2. 7
3. 8
4. 9
5. 17

What's the logic behind this to solve these problems? Can someone please explain? I struggle badly on these and they seem to appear on the real GMAT.

Apologies as I have posted in the wrong forum before.
avatar
shilpiruchi
Joined: 19 Apr 2011
Last visit: 15 Sep 2011
Posts: 7
Own Kudos:
16
 [1]
Given Kudos: 4
Status:GMAT - A logic game! Enjoy it!!
Posts: 7
Kudos: 16
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
gsaxena26
8k8
+k88
-------
1,6p6
-------

If k and p represent non-zero digits within the integers above, what is p?

1. 6
2. 7
3. 8
4. 9
5. 17

What's the logic behind this to solve these problems? Can someone please explain? I struggle badly on these and they seem to appear on the real GMAT.

Apologies as I have posted in the wrong forum before.

Well for this one, its just logic -

..8k8
+k88
-------
16p6

Now this means we have to add 2 numbers - one greater than 800 and the other unknown to get 1600. This second number should be near 800 by logic, infact a little less than 800 as the first number is a little more than 800, to get the sum to 1600.

you can even check by picking the bottom number to be 800 something or 900 something (by picking k as 8/9). It wont work as it will make the total way more than 1600 something.
e.g.
888+888=1776 => not the form of 16p6 => WRONG

lets try 7
878+788=1666 =>PERFECT k=7,p=6!


Ans: A
User avatar
GyanOne
Joined: 24 Jul 2011
Last visit: 22 Apr 2026
Posts: 3,237
Own Kudos:
Given Kudos: 33
Status: World Rank #4 MBA Admissions Consultant
Expert
Expert reply
Posts: 3,237
Kudos: 1,718
Kudos
Add Kudos
Bookmarks
Bookmark this Post
(Units digit of 9+k) = p

Also,
(Tens digit of 9+k) + 8 + k = 16
=> k = 8 - (Tens digit of 9+k)
=> k = 7

Therefore p = units digit of 16 = 6
The answer is (A)
User avatar
gmatcracker24
Joined: 29 Jun 2010
Last visit: 13 Apr 2017
Posts: 84
Own Kudos:
Given Kudos: 54
Status::)
WE:Information Technology (Consulting)
Products:
Posts: 84
Kudos: 112
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Hi gsaxena26,

There are no hard and fast rules to tackle such questions.These questions can easily be handled with quick substitution techniques.

8k8
k88 +
------
16P6
------

Now we start working from right to left :

Step 1 :

8+8 =16 ;we already have six as unit digit(in answer),the 1 gets carried off .

Step 2:

We should now think of a number for k which should help us to arrive at 16 when added in the end(since we have 16 in answer)
so lets quickly check how this could be done :

Let k=4 ;then (k+8)+1= 4+8+1=13 => P=3 and 1 will be carried to next 8+1+k=9+4=13 => Wrong (we want total to be 16)

Let k=7 ; then k+8+1=16 =>P=6 1 will be carried to next 8+1+k=8+7+1=16 => correct (we want total to be 16) .

Henece, P = 6.

The steps might seem to be time consuming,but belive me once you start calculating yourself this would be a cake walk and will not
take much of your time.
User avatar
bholakc
Joined: 09 Jun 2011
Last visit: 14 Sep 2011
Posts: 54
Own Kudos:
Posts: 54
Kudos: 512
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Confused! Does anybody explain better.
User avatar
jitbec
Joined: 06 Jun 2011
Last visit: 22 Aug 2013
Posts: 52
Own Kudos:
218
 [1]
Given Kudos: 15
Posts: 52
Kudos: 218
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Substitution technique means essntially trial and error here.
Out of 5 answer choices lets say P= 6 that is the answer choice A)
so the equation stabds as
8k8
k88
------
1666

now 8+8=16 so carry over is 1
now clearly k has to be 7 to make it 6 at the decimal place (7+8+1) =16
carry over is 1. so in the hudred place (8+ 7+1) = 16
which gives us the result 1666 which is correct
so p is 7
hope this clarifies

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
Math Expert
109744 posts