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qhoc0010
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riteshe
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vprabhala
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vprabhala
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the following should throw some ligh on how they are calculated.

https://mathforum.org/dr.math/faq/formul ... angle.html
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qhoc0010
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vprabhala
would go with C. (2a/sqrt(3))

if the circle would have been inscribed then Radius would have been
a/2 * sqrt(3)

If R = a/2 * sqrt(3)
Then Diameter must be 2R = a/sqrt(3) which is (B)



Quote:
Answer is C. Here is the trigonometry solution.
Let R be the radius of the circumscribed circle.

RCos30 = a/2 => R = a/sqrt(3)

Therefore diameter = 2a/sqrt(3)

This RCos30 = a/2 cannot be true
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