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rxs0005
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vprabhala
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rxs0005
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mallelac
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I am getting it as 60.

The units can be one among 1,3 and 5.
The tens can be among the remaining 5 because 1 is already chosen and no repetition is allowed.
The hundreds can be among the remaining 4 by the same reasoning.

So, the required = 4*5*3 = 60

rxs0005
How many 3 digit odd numbers can be formed from the set of digits { 1,2,3,4,5,6}
such that no repetetion of digits is allowed.
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twixt
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Agree with Malellac. In this case it is important to figure out that the constraint is on units digit and then just pick the remaining numbers.
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banerjeea_98
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5 x 4 x 3 = 60 ways. Unit digit can only be 1, 3, 5 so 3 ways.
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jinino
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mallelac
I am getting it as 60.

The units can be one among 1,3 and 5.
The tens can be among the remaining 5 because 1 is already chosen and no repetition is allowed.
The hundreds can be among the remaining 4 by the same reasoning.

So, the required = 4*5*3 = 60

rxs0005
How many 3 digit odd numbers can be formed from the set of digits { 1,2,3,4,5,6}
such that no repetetion of digits is allowed.


The other way around for the tenth and hundredth digits can also do it right. I got 60 as well.
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mallelac
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Could you explain the method? I am intrigued 8-) 8-)

jinino
mallelac
I am getting it as 60.

The units can be one among 1,3 and 5.
The tens can be among the remaining 5 because 1 is already chosen and no repetition is allowed.
The hundreds can be among the remaining 4 by the same reasoning.

So, the required = 4*5*3 = 60

rxs0005
How many 3 digit odd numbers can be formed from the set of digits { 1,2,3,4,5,6}
such that no repetetion of digits is allowed.

The other way around for the tenth and hundredth digits can also do it right. I got 60 as well.



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