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01 Dec 2022, 11:25
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
72% (02:19) correct
28%
(02:39)
wrong
based on 680
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Cars X and Y were traveling together on a straight road at a constant speed of 55 miles per hour when car X stopped for 5 minutes. If car Y continued to travel at 55 miles per hour, how many minutes from the time that car X resumed traveling did it take car X traveling at 60 miles per hour to catch up with car Y?(Assume
that the time for car X to slow down and speed up was negligible.)
(A) 5
(B) 30
(C) 45
(D) 55
(E) 60
that the time for car X to slow down and speed up was negligible.)
(A) 5
(B) 30
(C) 45
(D) 55
(E) 60
01 Dec 2022, 13:49
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Bunuel
Car X stopped for \(\frac{5}{60}\) hours
Distance Car Y travelled when Car X stopped = \(\frac{5}{60} * 55 = \frac{55}{12}\) miles
Relative speed between Car Y and Car X = 60 - 55 = 5mph
Time Car X will take to catch up = Time Car X will take to cover the gap distance = \(\frac{55}{12} * \frac{1}{5} = \frac{11}{12}\) hours
Time in minutes = \(\frac{11}{12} * 60 = 55\) mins
Option D
01 Dec 2022, 15:02
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Let time travelled by X be “T” and Y be “T + 5”
R * T = D
X : 60 * T = 60T
Y : 55 * T+5 = 55(T+5)
Distance travelled by X and Y is same.
60T = 55 (T+5)
T = 55
Answer D
Posted from my mobile device
R * T = D
X : 60 * T = 60T
Y : 55 * T+5 = 55(T+5)
Distance travelled by X and Y is same.
60T = 55 (T+5)
T = 55
Answer D
Posted from my mobile device
