CrackVerbalGMAT
Answer is D which is equal to 0.5.
Lets take this questions instead of 100 seat airplane. Lets take it as four seat airplane.
Chances of fourth person seat will not be occupied depends on the 2 nd person who comes after the first person.
If the 2nd person who comes after the first person sits in the first persons seat then the fourth person seat will not be occupied.
So there is 50% chance that fourth person seat is not occupied.
So there is 50% chance that fourth person seat is occupied.
Similarly for the 100 seat airplane.
So answer is D.
I am confused of this explanation.
- Firstly: why the chance that the 2nd person takes the first one's seat is 50%. If 3 seats are left, I think the chance must be 33%.
- Secondly: Make the above chance of 50% is right. But assume that the 2nd person doesn't take the first person's seat, rather takes the 3rd person's seat. Then if the 3rd one takes the 1st one's, then the 4th one will still find his/her seat available. Thus, I think a stop at the 2nd person is not enough.
I take the even more simple scenario and then could find the answer which is 0.5. Make it just 3-seat-plane.
- 1/3 is the chance that the 1st person choose his/her seat correctly =>the last one (3rd) will find his/her seat available;
- 1/3 the chance the 1st one takes 2nd one's seat. Here, 1/2 chance the 2nd takes the 1st one's, then 3rd one's is available; OR 1/2 chance the 2nd takes the 3rd one's, then 3rd one's is not available;
- 1/3 the chance the 1st one takes 3rd one's, then the 3rd one's is not available.
So the chance the 3rd person's seat is not available is: 1/3*1/2 + 1/3 = 1/6 + 1/3 = 0.5. (D).
I just don't know is it the same to the 100-seat-plane. Need a much more simple way. Thanks