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kimmyg
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chets
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vikramm
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2 + 2 + 2^2 + 2^3 + ....+ 2^9 =
1 + (1 + 2^1 + 2^2+2^3+....+2^9)
1 + (2^0 + 2^1 + 2^2+2^3+....+2^9) =
1 + [{(2^0 + 2^1 + 2^2+2^3+....+2^9) * (2 - 1)} / (2 - 1)] {multiply and divide by (2-1)}

1 + (2^ 10 - 1) = 2 ^ 10

edited: for more clarity
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i didn't get it.... can u explain it little bit more.
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HIMALAYA
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B. 2^10.

i also find the following the simpliest....

chets
b) 2^10
2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9
=2^2+2^2+2^3+2^4...+2^9
2^3=(2^2)+(2^2), and 2^4=(2^3+2^3)... similarly 2^8+2^8=2^9
by the above, we know that 2+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8 = 2^9
2^9+2^9=2(2^9)=2^10
This is the simplest method I could think of
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Got B. I just noticed that if you try to sum the numbers, you are just multiplying by 2.

Since this is not liek one of the other crazy exponents problems that I have seen before, I just added the numbers up and selected B.
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This is from GMAT PREP and the OA is given as A.

:?:
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MsStephanie
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B: 2^10 if you use a calculator, the answer is 1,024 = 2^10..perhaps there's a mistake in the answer key?

I used the same method as above:

2+2 = 4 = 2^2

I then calculated 2^2 + 2^2, which I noticed equals 2^3. I thought, "Wouldn't it be great if 2^3 + 2^3 = 2^4?" And it did! (This may have not come as a surprise to all of you advanced math ppl).

I continued with my "theory"..

2^4 + 2^4 = 2^5, 2^5 + 2^5 = 2^6, 2^6 + 2^6 = 2^7

2^7 + 2^7 = 2^8, 2^8 + 2^8 = 2^9...and for the last terms left...

2^9 + 2^9 = 2^10! :-D sorry..it's almost the end of my work day and i'm getting a little crazy



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