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14 Oct 2005, 20:36
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The size of diamonds is measured in karats. If the price of a diamond doubles for every.5karats, which of the following is worth the most?
A - one 4-karat diamond
B - fourteen 1-karat diamonds
C - four 2-karat diamonds and eight 1-karat diamonds
D - one 1-karat diamon, two 2-karat diamond, and three 3-karat diamond
E- three 1.5 karat diamonds and three 2.5 karat diamonds
I can't seem to find the shortucut. Please explain your answer. I will post OA on Sunday 9/16.
A - one 4-karat diamond
B - fourteen 1-karat diamonds
C - four 2-karat diamonds and eight 1-karat diamonds
D - one 1-karat diamon, two 2-karat diamond, and three 3-karat diamond
E- three 1.5 karat diamonds and three 2.5 karat diamonds
I can't seem to find the shortucut. Please explain your answer. I will post OA on Sunday 9/16.
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14 Oct 2005, 21:01
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The price doubles every .5 k. Assume price is x, then
.5k = x
1k = 2x
1.5k = 4x
2k = 8x and so on
1. 2^8 = 256x
2. 14 * 2^2 = 56x
3. 4*2^4 + 8*2^2 = 96x
4. 2^2 + 2*2^4 + 3*2^6 = 228x
5. 3*2^3 + 3*2^5 = 88x
Hence answer is A
.5k = x
1k = 2x
1.5k = 4x
2k = 8x and so on
1. 2^8 = 256x
2. 14 * 2^2 = 56x
3. 4*2^4 + 8*2^2 = 96x
4. 2^2 + 2*2^4 + 3*2^6 = 228x
5. 3*2^3 + 3*2^5 = 88x
Hence answer is A
