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Bunuel
What is the 57th digit to the right of the decimal point in the decimal equivalent of 13/55?

A. 2
B. 3
C. 4
D. 5
E. 6

13/55 = 0.236363….

We see that all even digits are 3 and all odd digits, except for the first one are 6.

Thus, the 57th digit (an odd number) is 6.

Answer: E
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To quickly convert between fractions and decimals, it is suggested that we memorise some key conversions: (From these, many many others can be derived.)

1/2 = 0.5
1/3 = 0.3333...
1/4 = 0.25
1/5 = 0.2
1/9 = 0.1111....
1/10 = 0.1
1/11 = 0.090909...

Now, let’s derive some more from these:

3/2 = 3(1/2) = 3(0.5) = 1.5
5/2 = 5(1/2) = 5(0.5) = 2.5
2/3 = 2(1/3) = 2(0.333...) = 0.6666...
1/6 = (1/2)*(1/3) = 0.5(0.333...) = 0.1666...
And so on.

Now this question wants 13/55.
This is not a direct multiple of any of our memorised fractions.
We can either take 13/55 as 13(1/5)(1/11) = 13(0.2)(0.0909...) OR do a small manipulation to make our numbers smaller.

13/55 = (11+2)/55
This is equal to (11/55) + (2/55).
= (1/5) + (2/55)
= 0.2 + (2/55)

Now, 2(0.2)(0.0909...) is easier to calculate than 13(0.2)(0.0909...).

We have 0.4(0.0909...) = 0.0363636...

Finally, 0.2 + 0.03636... gives us 0.2363636....

Conclusion : Since all odd places except just the first one have 6 as a digit, the 57th digit will also be a 6.
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Bunuel can you please show that conversion to 1/99 fraction here and solve
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sahiti220620
Bunuel can you please show that conversion to 1/99 fraction here and solve
sahiti220620 See if the below explanation helps:

Understanding the 1/99 Pattern

First, recall that \(\frac{1}{99} = 0.\overline{01}\) (01 repeats)

More generally: \(\frac{N}{99} = 0.\overline{N}\) where N is a 2-digit number that repeats.

For example: \(\frac{36}{99} = 0.\overline{36} = 0.363636...\)

Converting 13/55 Using This Technique

Step 1: Find the decimal representation
\(\frac{13}{55} = 0.2\overline{36}\)

Step 2: Separate the non-repeating and repeating parts
\(0.2\overline{36} = 0.2 + 0.0\overline{36}\)

Step 3: Express the repeating part using 1/99
\(0.0\overline{36} = \frac{0.\overline{36}}{10} = \frac{36/99}{10} = \frac{36}{990} = \frac{4}{110}\)

Step 4: Verify
\(\frac{13}{55} = \frac{2}{10} + \frac{4}{110} = \frac{22}{110} + \frac{4}{110} = \frac{26}{110} = \frac{13}{55}\) ✓

Finding the 57th Digit

Now we know: \(\frac{13}{55} = 0.2\overline{36}\)

- Position 1: \(2\) (non-repeating)
- Positions 2 onwards: \(36\) repeats

For position 57:
- We need the \((57-1) = 56^{th}\) digit of the repeating pattern "\(36\)"
- \(56 \div 2 = 28\) with remainder \(0\)
- This means we complete exactly 28 cycles of "\(36\)"
- The last digit of each cycle is \(6\)

Answer: E (6)

Pattern Recognition Technique

When you see a fraction that produces a repeating decimal, immediately think:
- 1-digit repeat → denominator with factor 9
- 2-digit repeat → denominator with factor 99
- 3-digit repeat → denominator with factor 999

This \(\frac{N}{99}\) technique works whenever you can isolate the repeating part!
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