ps - sum + sum ?

Question

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nero44 · Answer

BbBbBBBBBbBBbBbBBb.....

let q be sum of integers from 75 to 150
so p must simply be q + 151

1/q + 1/(q+151) ... rearrange and you get

2q + 151 / q^2 + q151

FN · Answer

LCM is q^2-151q

then q-151 goes into LCM q-151 times, and q goes q+151

so you have (q-151+q+151)/(q^2-151q)=2q/(q^2-151q)

nero44 · Answer

hehe I did this one again and now get a different result... letting q be the sum of integers..... I let p be q-151...

but then I get A....:S

gmacvik · Answer

Good one....

Q= p+151 so p=q-151

now solve 1/q-151 + 1/q ..... you will get A

HIMALAYA · Answer

A.

p= sum (75+76+77+............+150)
q= sum (75+76+77+............150+151)
q= sum (75+76+77+............150) +151
q= p+151
p= q-151

given that: 1/p+1/q = ?
= (p+q)/(pq)
replace p with q-151
= (q-151+q)/(q)(q-151)
= (2q-151)/(q^2- 151q)

christoph always has good questions.
a truck of thanxxxxxx :wink:

Antmavel · Answer

A too just consider p=q-151 and plug

HongHu · Answer

You just have to make sure you are clear which is the bigger one ...

ps - sum + sum ?

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