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Bunuel
Which of the following is equal to \(\frac{1}{9 - 4√5}\) ?

A. 9 + 4√5
B. 9 - 4√5
C. 9 + 2√5
D. 9 - 2√5
E. 4 + 9√5

We can multiply the numerator and denominator by 9 + 4√5.

When doing so, we can use the difference of two squares formula in the denominator, and we have

(9 + √5)/[9^2) - (4√5)^2]

(9 + √5)/[81 - 80] = 9 + √5

Answer: A
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How do you know that you have to multiply the numerator by:
9 + 4√5? Abhishek009
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How do you know that you have to multiply the numerator by:
9 + 4√5?Abhishek009[/url]


The denominator can be rationalized by its conjugate pair to remove a radical and make the fraction easier to understand:

This is done by taking the denominator 9 - 4√5 and multiplying it by its conjugate pair 9 + 4√5. This will result in the removal of a radical to "simplify" the denominator.

(9 - 4√5) x (9 + 4√5)

= (9 x 9) + ((9 x 4√5) - (9 x 4√5)) - (4√5 x 4√5)

= 81 - (16 x 5)

= 81 - 80

= 1

And since we multiply the denominator by the conjugate pair of 9 - 4√5 (i.e. multiplied by 9 + 4√5), we must multiply the numerator by 9 + 4√5

This results in the answer being 9 + 4√5 since 1 x (9 + 4√5) = 9 + 4√5.

This way of simplification is true for all "two-term" denominators with radicals

Conjugate pairs:

1/ (3 + √3) conjugate (3 - √3)

1/ (5√2 + 7) conjugate (5√2 - 7)

1/ (12 - 3√7) conjugate (12 + 3√7)

in essence, when multiplying a two-term radical by its conjugate pair, the radical cancels out. A conjugate pair to two-term radical is always the first term and the "opposite sign" of the second term.

Hope this helps.
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