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Q: [x]=0 ?
Given: [x] is an int, [x] >= x I interpreted no less than as >= and not as = Ambiguity: Is [2x] = 2*[x] ??
It would be helpful to know more about [x] thann what's already given.
Guess the trick here is to understand working of the question stem. all its saying is: [x] = x
rest is obvious:
(1) 2x = 0 or x = 0 (2) 3x = 0, x = 0
D.
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x doesn't have to be an integer in this problem (you still get the same answer though). [x] means find the closest integer not less than x so:
[-0.5] = 0
[0.5] = 1
Now for criteria #1:
Try x = -0.25
[2*-.25] = [-0.5] = 0, b/c 0 is the smallest integer not less than -0.5. Now try x = -0.5
[2*-0.5] = [-1] = -1, b/c -1 is the smallest integer not less than -1. This is no good so x must be greater than -0.5 and less than or equal to 0
Now for criteria #2:
Same story, x must be greater than -0.3333 and less than or equal to 0
So in each case you can say that [x] = 0, in criteria #1 try [-0.49], it equals 0. Now for criteria #2 try [-0.32], it also equals 0 as 0 is the smallest integer not less than x.
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