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GMATT73
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nakib77
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GMATT73
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nero44
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GMATT73
I used the same approach Nakib. Any "algebraic shortcuts" to save a minute or so instead of manually counting each unique path?


Someone else (sorry cant recall who it was) suggested a very good method on this problem. since you only want to take the shortest ways, and dont want to circle around the grid, you can go along the x axis 3 times and you can go up the y axis 2 times. 5 steps in total

example: go XXXYY

now you can treat the possible ways simply as a combination problem. To put differently, in how many ways can the 3 Xs and the 2 Ys be arranged?

5!/3!*2! = 5*4/2*1 = 10 ways
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GMATT73
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Thanks Nero,

So 5C2 to get the total number of Ys. ----->10
<or> 5C3 to get the numbers of Xs----->10

Either way we get the distinct number of possible movements. This method is a big time saver, I will include it in my flashcards. 8-)
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cool_jonny009
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similar question has been discussed on this form ...
method to calculate with out counting ...

Person has to take 2 horizontal steps and 3 vertical steps
HHVVV

Find the no of Different words that can be formed by the HHVVV word characters

= (total no of characters)!/(no of each repeated character)!

= 5!/2!3!

= 10




GMATT73
Imagine a 3X2 grid as such with X in the bottom left hand corner and Y in the top right hand corner: How many possible ways can a person walk from X to Y in 5 steps (horizontal or vertical only)? The OG just reccommends visually counting all 10 ways, but surely there must be a faster way?

l----l----l
l----l----l
l----l----l



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