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duttsit
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When do we get sum > 10..
in cases
1st 2nd 3rd
6 6 ---> Hence if we get a 6 first then = 1/6, probability
of getting 6or 5 or 4 in the second draw is 3/6.
6 5 Therefore total probability = 1/6 *3/6.. Now 6
can come in first, second or third draw.
6 4

Similarly, for 5 6 and 55 will result in bad cases.. 1/6 *2/6 *3

and in 46 can be a bad case .. 1/6 *1/6

Hence total = 1/6 *3/6 * 3 + 1/6 *2/6 *3 + 1/6 *1/6 = 1/2

1-1/2 = 1/2.

I wont be surprised if i went wrong somewhere
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rianah100
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I would probably guess if this shows up in the real test:
Figuring out 3-10 inclusive as hard as the NOT case (11..18 inclusive). Seems like too many possibilities. Does anyone know of an easy way?
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GMATT73
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My method (45 seconds)

Lowest possible total: 3 (1-1-1)
Highest possible total: 18 (6-6-6)

Difference, inclusive of 3 and 18 = 16

Probability= #desired outcomes/#total possible outcomes

Desired outcomes (3-10)= 8
Possible outcomes= 16

8/16---> 1/2

(unless a dice falls off the table and the cat gobbles it up before you can read it) 8-)
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duttsit
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GMATT73
My method (45 seconds)

Lowest possible total: 3 (1-1-1)
Highest possible total: 18 (6-6-6)

Difference, inclusive of 3 and 18 = 16

Probability= #desired outcomes/#total possible outcomes

Desired outcomes (3-10)= 8
Possible outcomes= 16

8/16---> 1/2

(unless a dice falls off the table and the cat gobbles it up before you can read it) 8-)


bingo...you gottit..good job matt. bewakoof was close as well.

if we try a few steps we get a pattern that:
in this case(when three dices are thrown):

p(getting score n) = p(getting score (21-n))

for example:
p(getting score 3) = 1-1-1= 1/6*1/6*1/6
p (getting 10 - 3 = 18) = 6-6-6 = 1/6 * 1/6 * 1/6

so p(getting score 3-10) = p (score 11-18)
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oppss!!!! My answer is way off..

but can somebody tell me why the answer by this approach comes wrong..
....
Mats method is good ..but just to clear my concept here ...i wann know what is wrong in this approach....
'


cool_jonny009
7/8

all the result having 4 5 6 will have sum more than 10

so total no of combination with 456 ( incuding the repeating each number) = 3*3*3=27

total no of possible out comes = 6*6*6=216

so P = 1 - 1/8= 7/8

what is OA ..?
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cool_jonny009
oppss!!!! My answer is way off..

but can somebody tell me why the answer by this approach comes wrong..
....
Mats method is good ..but just to clear my concept here ...i wann know what is wrong in this approach....
'


cool_jonny009
7/8

all the result having 4 5 6 will have sum more than 10

so total no of combination with 456 ( incuding the repeating each number) = 3*3*3=27

total no of possible out comes = 6*6*6=216

so P = 1 - 1/8= 7/8

what is OA ..?


How do you account for numbers like 614 and 156? the bold sentence does not cover all options.
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amy_v
cool_jonny009
oppss!!!! My answer is way off..

but can somebody tell me why the answer by this approach comes wrong..
....
Mats method is good ..but just to clear my concept here ...i wann know what is wrong in this approach....
'


cool_jonny009
7/8

all the result having 4 5 6 will have sum more than 10

so total no of combination with 456 ( incuding the repeating each number) = 3*3*3=27

total no of possible out comes = 6*6*6=216

so P = 1 - 1/8= 7/8

what is OA ..?

How do you account for numbers like 614 and 156? the bold sentence does not cover all options.


what he (or she) meant was each die rolled 4 and up. This is how he arrived at 3*3*3. If we used your example of 614, we won't get 3*3*3.



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