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Bunuel
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Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
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chetan2u Bunuel Should we just figure of the area of the rectangle (7*12=84) and area of the required triangle (1*3*4/2=6) and arrive at the triangles 84/6=14 or should we check if such triangles are possible from the balance area say : first can you cut all the area of the rectangle in right angles triangles of the required measurements? or some area will be unusable?


its fine either way, because there is no unusable area
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Arvind42
chetan2u Bunuel Should we just figure of the area of the rectangle (7*12=84) and area of the required triangle (1*3*4/2=6) and arrive at the triangles 84/6=14 or should we check if such triangles are possible from the balance area say : first can you cut all the area of the rectangle in right angles triangles of the required measurements? or some area will be unusable?




its fine either way, because there is no unusable area

But how do we determine that there is no unusable area?. This question it might work but others?

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Bunuel

What is the maximum number of right triangles with legs of length 3 ft and 4 ft that can be cut from the rectangular sheet of metal represented in the figure attached?

(A) 7
(B) 8
(C) 10
(D) 12
(E) 14

Attachment:
217695.18.gmc74207s.gif

area of ∆ = 1/2 * 3*4 ; 6
area of rectangle ; 7*12 ; 84
so max fig which can be cut ; 84/6 ; 14
IMO E
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Rather than 3-4-5 triangle, Let's consider a rectangle with sides 3 and 4. Each rectangle can be further cut into 2 triangles.

Along the base 7:

Placing rectangle with side 3 cm will stack up 3 rectangles in height: 12/4= 3

Now, along base 7: on remaining 4 cm, we can stack up 4 rectangles: 12/3= 4.

Total 4x3 rectangles: 7
Therefore, total triangles: 14

Ans E

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