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faisalt
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GMATT73
Probability= #desired results/#possible results (Fastest method)


Total ways to get exactly 2 heads out of 4 flips--->4C2=6

Total possible results--->2^4=16

Put into probability formula--->6/16

Simplify--->3/8


I came across this problem. I am not sure of the logic behind the bolded part above. I understand total possible results are 2^4, but can someone please explain how the total ways to get exactly 2 heads out of 4 flips is 4C2? Thanks
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GMATT73
Probability= #desired results/#possible results (Fastest method)


Total ways to get exactly 2 heads out of 4 flips--->4C2=6

Total possible results--->2^4=16

Put into probability formula--->6/16

Simplify--->3/8

I came across this problem. I am not sure of the logic behind the bolded part above. I understand total possible results are 2^4, but can someone please explain how the total ways to get exactly 2 heads out of 4 flips is 4C2? Thanks


What we're concerned here is how to pick a group of n objects from a pool of p objects. The way to calculate this is to use combinations and 4C2 represents 2 heads out of 4 tosses.

Another way to do this:
Possible arrangements:
TTHH
THTH
HTHT
HHTT
HTTH
THHT

Total number of arrangements = 16
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faisalt
Marco tosses a coin four times. What is the probability that he get heads exactly twice?

A. 1/4
B. 3/8
C. 7/16
D. 1/2
E. 5/8


Total number of combinations = 16
Number of ways to choose heads twice = 4c2 = 6
= 6/16 = 3/8
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ywilfred
yb
GMATT73
Probability= #desired results/#possible results (Fastest method)


Total ways to get exactly 2 heads out of 4 flips--->4C2=6

Total possible results--->2^4=16

Put into probability formula--->6/16

Simplify--->3/8

I came across this problem. I am not sure of the logic behind the bolded part above. I understand total possible results are 2^4, but can someone please explain how the total ways to get exactly 2 heads out of 4 flips is 4C2? Thanks

What we're concerned here is how to pick a group of n objects from a pool of p objects. The way to calculate this is to use combinations and 4C2 represents 2 heads out of 4 tosses.

Another way to do this:
Possible arrangements:
TTHH
THTH
HTHT
HHTT
HTTH
THHT

Total number of arrangements = 16


Thanks ywilfred. This is how I understand it... 4 ways to pick the first head, 3 to pick the second, divide by 2 to prevent double counting.



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