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02 Nov 2021, 03:45
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
67% (01:48) correct
33%
(02:04)
wrong
based on 540
sessions
History
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A stack of 10 kgs of grapes contained 99% water. After 3 days, only water evaporated & the new water content constituted 90% of the total weight. What was the new weight of the stack?
(A) 9.9 kgs.
(B) 9 kgs.
(C) 8.1 kgs.
(D) 1 kg.
(E) 0.1 kg
(A) 9.9 kgs.
(B) 9 kgs.
(C) 8.1 kgs.
(D) 1 kg.
(E) 0.1 kg
21 Dec 2024, 02:26
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GMAT2025HJ
A stack of 10 kgs of grapes contained 99% water. After 3 days, only water evaporated & the new water content constituted 90% of the total weight. What was the new weight of the stack?
(A) 9.9 kgs.
(B) 9 kgs.
(C) 8.1 kgs.
(D) 1 kg.
(E) 0.1 kg
Initially, the stack of 10 kg of grapes contained 99% water and 1% pulp. This means the water content was 9.99 kg, and the pulp weighed 0.1 kg.
After 3 days, only water evaporated, so the amount of pulp remained constant at 0.1 kg. Now, the pulp constitutes 10% of the total weight. If 0.1 kg represents 10%, the total weight (100%) is 1 kg.
Answer: D.
Hope it's clear.
General Discussion
02 Nov 2021, 04:18
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previously:
9,9 kg water : 10 kg total weight = 99%
after: x = weight lost
9,9kg water - x kg : 10 kg total weight - x kg
=
(9,9 kg water - x) / (10 kg total weight - x) = 90%
(9,9 - x) / (10 - x) = 0,9
9,9 - x = (10 - x) * 0,9 = 0,9*10 - 0,9*x = 9 - 0,9x
9,9 - 9 = x - 0,9x
0,9 = 0,1 x --> x = 9 --> weight lost = 9
10 - 9 = 1 kg left
9,9 kg water : 10 kg total weight = 99%
after: x = weight lost
9,9kg water - x kg : 10 kg total weight - x kg
=
(9,9 kg water - x) / (10 kg total weight - x) = 90%
(9,9 - x) / (10 - x) = 0,9
9,9 - x = (10 - x) * 0,9 = 0,9*10 - 0,9*x = 9 - 0,9x
9,9 - 9 = x - 0,9x
0,9 = 0,1 x --> x = 9 --> weight lost = 9
10 - 9 = 1 kg left
