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04 Oct 2017, 10:26
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As I was practicing I came across the following question:
At a certain school, the ratio of students to teachers is 3:5, and the ratio of teachers to administrators is 4:5. Which of the following could be the total number of students at the school? (Indicate all that apply):
A. 150
B. 180
C. 200
D. 240
E. 300
I got the right answer, but my method was somewhat convoluted. The explanation offered by the website seems much easier (especially because these types of ratio problems confuse me). This their explanation:
The Correct answers are B, D, and E. Whenever a question provides multiple ratios with a common element, manipulate the ratios so that the common element has the same value in both ratios. In this case, the common element is teachers, so we should manipulate the ratios so that the number of teachers is the least common multiple of 5 and 4: 20. In the first ratio: students/teachers = 3/5 = 12/20. In the second ratio: teachers/administrators = 4/5 = 20/25. The ratio of students to teachers to administrators is thus 12:20:25. The number of students must therefore be a multiple of 12. Any choice that is a multiple of 12 is a potential value for the number of students. The correct answer is B, D, and E.
The bold part of the explanation is the part that I don't fully buy because I can't come up with the logic for why that must be the case. Can anyone verify (and perhaps attempt to explain why) that this is a valid method and will always work for this type of question.
Much appreciated!
At a certain school, the ratio of students to teachers is 3:5, and the ratio of teachers to administrators is 4:5. Which of the following could be the total number of students at the school? (Indicate all that apply):
A. 150
B. 180
C. 200
D. 240
E. 300
I got the right answer, but my method was somewhat convoluted. The explanation offered by the website seems much easier (especially because these types of ratio problems confuse me). This their explanation:
The Correct answers are B, D, and E. Whenever a question provides multiple ratios with a common element, manipulate the ratios so that the common element has the same value in both ratios. In this case, the common element is teachers, so we should manipulate the ratios so that the number of teachers is the least common multiple of 5 and 4: 20. In the first ratio: students/teachers = 3/5 = 12/20. In the second ratio: teachers/administrators = 4/5 = 20/25. The ratio of students to teachers to administrators is thus 12:20:25. The number of students must therefore be a multiple of 12. Any choice that is a multiple of 12 is a potential value for the number of students. The correct answer is B, D, and E.
The bold part of the explanation is the part that I don't fully buy because I can't come up with the logic for why that must be the case. Can anyone verify (and perhaps attempt to explain why) that this is a valid method and will always work for this type of question.
Much appreciated!
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
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04 Oct 2017, 10:41
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tkfull
Please post GRE questions on GRE site: https://greprepclub.com/
GRE forums: https://greprepclub.com/forum/?fl=menu
GRE quantitative section: https://greprepclub.com/forum/gre-quant ... section-3/
Hope it helps.
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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