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Total words = 5

Repeat word E (twice) and L (twice)

So = 5!/(2!*2!) = 30
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L - 2
E - 2
V - 1

Total number of ways = 5!/2!2! = 30
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Example: To find all permutations on A B C C
Answer: ABCC, ACBC, ACCB,
BACC, BCAC, BCCA,
CABC, CBAC, CBCA,
CACB, CCAB, CCBA
There are 12 orders, or 12 permutations in total.

P( permutation of n objects with n1 identical ones)

= n!/ n1!

Example of ABCC:
n = 4; (A,B,C,C)
n1= 2; (C,C)
n!/ n1! = 4! / 2! = (4 x 3 x 2 x 1)/ (2 x 1) = 12



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