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| 4x - 2 | = 10

Step 1: Open the modulus along with the conditions

Case 1:
4x - 2 = 10 ; x>0
4x = 12
x = 3

Case 2:
4x - 2 = -10 ; x<0
4x = -8
x= -2

Step 2:
Check the options
-2 is one of the options.

Ans: -2 Option B
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What If 3 and -2, both options will be there?
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Hi Amey.revankar,

In this question, notice how the prompt asks "what COULD be the value of X....?" Obviously, there are two solutions to this Absolute Value equation, but the prompt did NOT ask "what ARE the values of X...?" The specific phrasing in the prompt means that both solutions would NOT be among the 5 answers (only one of them would be).

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Given that |4x – 2| = 10 and we need to find which value of x out of the option choices satisfies this.

We can divide both the sides by 2 to get
\(\frac{|4x – 2|}{2} = \frac{10}{2}\)
=> |2x - 1| = 5

Let's understand how to solve this problem using two methods

Method 1: Substitution

Let's take each answer choice and substitute in the question and check which one satisfies the question

A. −3 Put x = -3 in |2x - 1| = 5. We get
|2*(-3) - 1| = 5 => | -6 - 1| = |-7| = 7 \(\neq\) 5 => NOT POSSIBLE

B. −2 Put x = -2 in |2x - 1| = 5. We get
|2*(-2) - 1| = 5 => | -4 - 1| = |-5| = 5 = 5 => POSSIBLE
We don't need to solve further but solving to complete the problem

C. 1 Put x = 1 in |2x - 1| = 5. We get
|2*1 - 1| = 5 => | 2 - 1| = |1| = 1 \(\neq\) 5 => NOT POSSIBLE

D. 2 Put x = 2 in |2x - 1| = 5. We get
|2*2 - 1| = 5 => |4 - 1| = |3| = 3 \(\neq\) 5 => NOT POSSIBLE

E. 4 Put x = 4 in |2x - 1| = 5. We get
|2*4 - 1| = 5 => |8 - 1| = |7| = 7 \(\neq\) 5 => NOT POSSIBLE

Method 2: Algebra

|2x - 1| = 5

Now, there are two ways of solving this

Method 2.1: Squaring

Square both the sides we get
\((|2x-1|)^2 = 5^2\)
=> \((2x-1) ^ 2 \)= 25
=> \((2x)^2 + 1^2 - 2*2x*1\) = 25
=> \(4x^2\) - 4x + 1 -25= 0
=> \(4x^2\) - 4x -24 = 0
Divide both sides by 4 we get
=> \(x^2\) - x - 6 =0
=> \(x^2\) -3x +2x - 6 =0
=> x*(x-3) 2*(x-3) = 0
=> (x-3) * (x+2) = 0
=> x = -2, 3

Method 2.2: Opening Absolute Value

|2x - 1| = 5
=> 2x-1 = 5 or 2x-1 = -5
=> 2x = 5+1 = 2 or 2x = -5+1 = -4
=> 2x = 6 or 2x = -4
=> x = \(\frac{6}{2}\) = 3 or x = \(\frac{-4}{2}\)
=> x = 3 or x = -2

So, Answer will be B
Hope it helps!

Watch the following video to learn the Basics of Absolute Values

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