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02 Jul 2021, 08:57
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
71% (02:02) correct
29%
(02:22)
wrong
based on 173
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Two positive integers when divided by a certain divisor leave remainders of 431 and 379 respectively. When the sum of these two numbers is divided by the same divisor, the remainder is 211. What is the divisor?
(A) 263
(B) 599
(C) 611
(D) 1021
(E) 1025
(A) 263
(B) 599
(C) 611
(D) 1021
(E) 1025
02 Jul 2021, 09:04
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Given: Two positive integers when divided by a certain divisor leave remainders of 431 and 379 respectively.
When the sum of these two numbers is divided by the same divisor, the remainder is 211.
Asked: What is the divisor?
Let the 2 positive integers be x & y and divisor be d.
x mod d = 431
y mod d = 379
(x + y) mod d = 431 + 379 - nd = 810 - nd; where n is an integer
(x+y) mod d = 211
810 - nd = 211
nd = 810 - 211 = 599
Since divisor is greater than 431; the divisor is 599.
IMO B
When the sum of these two numbers is divided by the same divisor, the remainder is 211.
Asked: What is the divisor?
Let the 2 positive integers be x & y and divisor be d.
x mod d = 431
y mod d = 379
(x + y) mod d = 431 + 379 - nd = 810 - nd; where n is an integer
(x+y) mod d = 211
810 - nd = 211
nd = 810 - 211 = 599
Since divisor is greater than 431; the divisor is 599.
IMO B
02 Jul 2021, 09:08
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Explanation:
431+379 = 810
810-211= 599
IMO-B
Posted from my mobile device
431+379 = 810
810-211= 599
IMO-B
Posted from my mobile device
