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laxieqv
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GMATT73
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10+11+14=35 total

35-20-3= 12

What am I missing here?
deduct 3 twice.

Why do we need to make the second deduction?


when u add a, b and c, you counted abc (=3) three times but you should count only once. so you need to deduct 2 (3).
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ipc302
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There was a similar question posted few days back ...

The answer is 3 .


say
x study both A &B
y study both A &C
z study both B&C

so the people ONLY studyA is 10 -( 3 +x+y)
the people ONLY study B is 11 -(3 +x +z)
the people ONLYstudy C is 14 -(3 +y +z)

But according to question only 20 people study only one subject so
if we add all the 3 above we get 26 -2 *(x+y+z) = 20

it means x + y+ z = 3

so 3 people study 2 kinds .
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x - Only A
y - Only B
z- Only C

a - A and B
b - B and C
c - C and A

We have to find (a + b + c) = W

We get (x+y+z) + (a + b + c) + 3 = Total
20 + (a + b + c) + 3 = T

T = 23 + (a + b + c) i.e T = 23+W........EQ1

Also
10+11+14 -2 * 3 - (a+b+c) = T i.e T = 29 - W.... EQ2

Solve these two equations and we get W = 3
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ywilfred
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Represent intersect using '^'

A + (A^B^C) + (A^B) + (A^C) = 10
A + (A^B) + (A^C) = 7 ----(1)

B + (A^B^C) + (A^B) + (B^C) = 11
B + (A^B) + (B^C) = 8 ----(2)

C + (A^B^C) + (B^C) + (C^A) = 14
C + (B^C) + (C^A) = 11 ----(3)

(1) + (2) + (3)

(A + B + C) + 2(A^B) + 2(A^C) + 2(B^C) = 26
(A^B) + (A^C) + (B^C) = 3

Number of people learning two of the three = 3
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3.

Venn diagram where a,b and c represent people learning two things.

10-(3+a+c) + 11 -(3+c+b) + 14-(3+a+b) = 20.
26-20 = 2(a+b+c)

a+b+c = 3 = Total number of people learning two of three things.
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Professor
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hmmmmm.......... all for 3 but i still stick with 9. laxi, did you forget to explain this with OA?
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SimaQ
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I think the answer shoud be 9....

You guys who calculated a+b+c=3 got what the statement was telling, i.e. that 3 people learn all three disciplines...
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laxieqv
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ipc302
There was a similar question posted few days back ...

The answer is 3 .


say
x study both A &B
y study both A &C
z study both B&C


so the people ONLY studyA is 10 -( 3 +x+y)
the people ONLY study B is 11 -(3 +x +z)
the people ONLYstudy C is 14 -(3 +y +z)

But according to question only 20 people study only one subject so
if we add all the 3 above we get 26 -2 *(x+y+z) = 20

it means x + y+ z = 3

so 3 people study 2 kinds .


this OE is the clearest one. Thus OA is 3

I just want to complement a little to the bold part:
x= study both A and B without C
y= study both A and C without B
z= study both B and C without A
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HIMALAYA
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laxieqv
ipc302
There was a similar question posted few days back ...

The answer is 3 .


say
x study both A &B
y study both A &C
z study both B&C


so the people ONLY studyA is 10 -( 3 +x+y)
the people ONLY study B is 11 -(3 +x +z)
the people ONLYstudy C is 14 -(3 +y +z)

But according to question only 20 people study only one subject so
if we add all the 3 above we get 26 -2 *(x+y+z) = 20

it means x + y+ z = 3

so 3 people study 2 kinds .

this OE is the clearest one. Thus OA is 3

I just want to complement a little to the bold part:
x= study both A and B without C
y= study both A and C without B
z= study both B and C without A


laxi, good to see you after a long time. and i am still waiting for your words. :wink:



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