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vivek123
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I can hit a target once in 4 shots. If I fire 4 shots in 09 Mar 2006, 06:16
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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I can hit a target once in 4 shots. If I fire 4 shots in succession, what is the probability that I will hit my target?

(A) 1
(B) 1/256
(C) 81/256
(D) 93/156
(E) 175/256



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SimaQ
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I can hit a target once in 4 shots. If I fire 4 shots in 09 Mar 2006, 06:25
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vivek123
I can hit a target once in 4 shots. If I fire 4 shots in succession, what is the probability that I will hit my target?

(A) 1
(B) 1/256
(C) 81/256
(D) 93/156
(E) 175/256
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I am sure there is a trap but i choose A :)
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Yurik79
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I can hit a target once in 4 shots. If I fire 4 shots in 09 Mar 2006, 08:21
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why not B?The prob to hit the target is 1/4
so 1/4^4=1/256
where am I wrong guys please))
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BG
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I can hit a target once in 4 shots. If I fire 4 shots in 09 Mar 2006, 08:25
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Hallo Jurik, think that this is the prob to hit the target ALL the four times. Your answer would have been correct if the Q was: What is to prob of having 4 hits-(1/4)^4
Hope that helps
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Yurik79
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I can hit a target once in 4 shots. If I fire 4 shots in 09 Mar 2006, 08:33
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:stupid2 :thanks now I get it
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chuckle
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I can hit a target once in 4 shots. If I fire 4 shots in 09 Mar 2006, 19:29
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I too would go for 1. What is OA and OE?
Its a little inconvenient to choose 1 in probability questions.
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vivek123
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I can hit a target once in 4 shots. If I fire 4 shots in 09 Mar 2006, 19:48
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This is one silghtly tougher question but worth trying, let's try again. The OA is not "A".
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ywilfred
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I can hit a target once in 4 shots. If I fire 4 shots in 10 Mar 2006, 20:06
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P(hit target) = 1/4
P(miss target) = 3/4

I hit the target as long as I hit it once.

P(hit at least once) = 1 - (3/4)^4 = 1 - 81/256 = 175/256
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I can hit a target once in 4 shots. If I fire 4 shots in 12 Mar 2006, 16:31
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1 - p(no hitting the target in 4 events)

use binomial

4c0 * (1/4)^0 * (3/4)^4

1 - (3/4)^4

also can be thought of:

P(hitting the target 1 time in 4 shots) +P(hitting the target 2 times in 4 shots)+
P(hitting the target 3 times in 4 shots) + P(hitting the target 4 times in 4 shots)

given the probability of 25% chance in 1 attempt



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