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06 Apr 2006, 20:06
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If 125% of j is equal to 25% of k, 150% of k is equal to 50% of l, and 175% of l is equal to 75% of m, then 20% of m is equal to what percent of 200% of j ?
.35
3.5
35
350
3500
.35
3.5
35
350
3500
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06 Apr 2006, 21:41
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Riuscita
suppose j = 100
1.25 j = 0.25 k
k = 125/0.25 = 500
1.5k =0.5 l
l = 750/0.5 = 1500
1.75 l = 0.75 m
1.75 (1500) = 0.75 m
m = 3500
20% of m = (x%/100) of 200% of j
0.2 (3500) = (x%/100) (2x100)
700/200 = (x%/100)
3.5 = (x%/100)
x % = 350 %
07 Apr 2006, 14:36
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If 125% of j is equal to 25% of k
Therefore
125j/100 = 25k/100
i.e 1.25j = k/4 -------- Eqn 1
150% of k is equal to 50% of l
Therefore
150k/100 = 50l/100
i.e 1.5k = l/2 -------------Eqn 2
175% of l is equal to 75% of m,
Therefore
175l/100 = 75m/100
i.e 1.75l = 3m/4 ---------Eqn 3
From eqn 3 ----> m = 7l/3--------Eqn 4
To calculate 20% of m
From Eqn 4 ------> 20%m = (20/100)(7l/3)
20%m = 7l/15 ---------Eqn 5
To calculate 200% of j
From Eqn 1 ------> j= k/5
200 % of j = (200/100)(k/5)
= 2k/5
From Eqn---2 we know k = l/3
Sub for k in 200% of j we get
200% of j = 2l/15 ------------Eqn 6
Finally 20% of m is equal to what percent of 200% of j ?
(Eqn5 .100)/(Eqn 6)
i.e [(7l/15) . 100]/(2l/15)
Simplifying 7.100/2
which is 3.5 x 100
= 350
Answer is D
& Done
Heman & the master of the universe
Therefore
125j/100 = 25k/100
i.e 1.25j = k/4 -------- Eqn 1
150% of k is equal to 50% of l
Therefore
150k/100 = 50l/100
i.e 1.5k = l/2 -------------Eqn 2
175% of l is equal to 75% of m,
Therefore
175l/100 = 75m/100
i.e 1.75l = 3m/4 ---------Eqn 3
From eqn 3 ----> m = 7l/3--------Eqn 4
To calculate 20% of m
From Eqn 4 ------> 20%m = (20/100)(7l/3)
20%m = 7l/15 ---------Eqn 5
To calculate 200% of j
From Eqn 1 ------> j= k/5
200 % of j = (200/100)(k/5)
= 2k/5
From Eqn---2 we know k = l/3
Sub for k in 200% of j we get
200% of j = 2l/15 ------------Eqn 6
Finally 20% of m is equal to what percent of 200% of j ?
(Eqn5 .100)/(Eqn 6)
i.e [(7l/15) . 100]/(2l/15)
Simplifying 7.100/2
which is 3.5 x 100
= 350
Answer is D
& Done
Heman & the master of the universe
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
