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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 16 Apr 2006, 13:03
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(7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent.



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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 16 Apr 2006, 14:04
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0...

7 * 7 *2! * 4! * 6!
----------------------
9!*14

1/3
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Yurik79
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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 16 Apr 2006, 21:52
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(7^2)*2!*4!*6!/9!
7*7*2*2*3*4*2*3*4*5*6/2*3*4*5*6*7*8*9*2*7=2/3
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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 16 Apr 2006, 22:06
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1/3 it is :)

Straight forward question...
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sm176811
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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 17 Apr 2006, 02:13
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The expression can be reduced to 1/3.

The quotient is 0 and the remainder is 1.
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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 18 Apr 2006, 00:11
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sm176811
The expression can be reduced to 1/3.

The quotient is 0 and the remainder is 1.
Show more


It is true that the quotient is 0. However why is the remainder 1?

The original expression is 14/3. When divided by 14 it reduces to 1/3. However the point to remember is that it is being divided by 14. So 14 is the divisor. So while the quotient is 0, the remainder should be 14/3 (as 14/3 is less than 14).

For 14/3 = 14*0 + 14/3
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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 18 Apr 2006, 00:15
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Zooroopa
sm176811
The expression can be reduced to 1/3.

The quotient is 0 and the remainder is 1.


It is true that the quotient is 0. However why is the remainder 1?

The original expression is 14/3. When divided by 14 it reduces to 1/3. However the point to remember is that it is being divided by 14. So 14 is the divisor. So while the quotient is 0, the remainder should be 14/3 (as 14/3 is less than 14).

For 14/3 = 14*0 + 14/3
Show more


Remainder is never a fraction!

Remainder = f(x) - quotient*divisor.
= 1 - 0*3

When all the above are integers, the remainder cannot be a fraction!
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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 18 Apr 2006, 00:15
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Remainder is never a fraction!

Remainder = f(x) - quotient*divisor.
= 1 - 0*3

When all the above are integers, the remainder cannot be a fraction!
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7^2)*2!*4!*6!/9! is divided by 14. Find the quotinent 18 Apr 2006, 18:41
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sm176811
Zooroopa
sm176811
The expression can be reduced to 1/3.

The quotient is 0 and the remainder is 1.


It is true that the quotient is 0. However why is the remainder 1?

The original expression is 14/3. When divided by 14 it reduces to 1/3. However the point to remember is that it is being divided by 14. So 14 is the divisor. So while the quotient is 0, the remainder should be 14/3 (as 14/3 is less than 14).

For 14/3 = 14*0 + 14/3

Remainder is never a fraction!

Remainder = f(x) - quotient*divisor.
= 1 - 0*3

When all the above are integers, the remainder cannot be a fraction!
Show more


Well it is being divided by 14. So if the remainder is 1, then we ought to have

14/3 = 14*0 (quotient) + 14*1 (remainder)

Now is that the case?



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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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