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22 May 2006, 15:43
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Q. Five out of 35 students can be seated in the first row. What is the probability that "A" sits in the first row?
I followed the following approach :-
Total no. of ways = 35C5
No. of ways when for "A" to sit in the first row = 5C1
No. of ways for remaining 34 students to be seated in the room = 34C4 (taking "A" out)
Thus, probability = (5C1 * 34C4)/35C5
However this is not the correct answer. Can someone please point out where I am going wrong? Will post the OA later.
I followed the following approach :-
Total no. of ways = 35C5
No. of ways when for "A" to sit in the first row = 5C1
No. of ways for remaining 34 students to be seated in the room = 34C4 (taking "A" out)
Thus, probability = (5C1 * 34C4)/35C5
However this is not the correct answer. Can someone please point out where I am going wrong? Will post the OA later.
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22 May 2006, 15:57
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I think it should be 34C4/35C5.
Since order does not matter, you don't need to use 5C1. If you are concerned with order, it would be -
(5 * 34P4)/35P5
Since order does not matter, you don't need to use 5C1. If you are concerned with order, it would be -
(5 * 34P4)/35P5
22 May 2006, 19:16
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Yup, you got it right! Answer is 34C4/35C5
And in case order matters, the answer is 5P1 * 34P4/35P5, or 5 * 34P4/35P5.
And in case order matters, the answer is 5P1 * 34P4/35P5, or 5 * 34P4/35P5.
