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Bunuel
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What is the product of the average (arithmetic mean) and the median of 14 Oct 2025, 00:29
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45% (medium)

Question Stats:

68% (02:08) correct 32% (02:26) wrong based on 209 sessions

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What is the product of the average (arithmetic mean) and the median of the set composed of the distinct prime factors of 4,095?

A. 25
B. 28
C. 31
D. 35
E. 42


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E
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What is the product of the average (arithmetic mean) and the median of 14 Oct 2025, 01:37
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Find the distinct prime factors of 4,095:
4,095 = 5 × 3 × 273
273 = 3 × 91
91 = 7 × 13
So, the distinct prime factors are 3, 5, 7, 13.

Average = (3 + 5 + 7 + 13) / 4 = 28 / 4 = 7

Median = (5 + 7) / 2 = 12 / 2 = 6

Average × Median = 7 × 6 = 42

Final answer: 42
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What is the product of the average (arithmetic mean) and the median of 14 Oct 2025, 07:01
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Bunuel
What is the product of the average (arithmetic mean) and the median of the set composed of the distinct prime factors of 4,095?

A. 25
B. 28
C. 31
D. 35
E. 42


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Let’s take the factors of 4095.

4095 = 5 * 3^2 * 7 * 13

The distinct prime numbers are {3, 5, 7, 13} .

The average of the prime numbers = (3+5+7+13)/4 = 28/4 = 7

The median of the set is (5+7)/2 = 6

Therefore the product of average and median = 7*6 = 42

Option E
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What is the product of the average (arithmetic mean) and the median of 14 Oct 2025, 09:25
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Prime factorisation of 4095= 5*3*3*7*13
The prime factorisation of 4095 includes (3,5,7,13) as distinct prime numbers
Average of distinct prime numbers= (3+5+7+13)/4=7
And median= (5+7)/2=6
The product of the average and the median of the distinct prime factors of 4,095= 7*6=42

Answer: E
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What is the product of the average (arithmetic mean) and the median of 14 Oct 2025, 17:28
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If we breakdown this number 4095 the prime factors we get are 3,5 , 7,13.
The average of this set is 28/4=7
median is 5+7=12/2=6

product is 7*6=42 option E
Bunuel
What is the product of the average (arithmetic mean) and the median of the set composed of the distinct prime factors of 4,095?

A. 25
B. 28
C. 31
D. 35
E. 42


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What is the product of the average (arithmetic mean) and the median of 19 Oct 2025, 11:55
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Here is the solution of the question:-

Factorizing 4,095, we note it ends with 5, so it is divisible by 5:
4095 ÷ 5 = 819.

The sum of digits of 819 is 18, divisible by 3,
so 819 ÷ 3 = 273.

Similarly, 273 ÷ 3 = 91, and 91 = 7 × 13.

Thus, the prime factorization is 4095=3 * 3 * 5 * 7 * 13 , and the distinct prime factors are {3, 5, 7, 13}.

The arithmetic mean of these numbers is (3+5+7+13)/4 = 28/4 = 7.
Arranging the numbers in increasing order gives 3, 5, 7, 13, so the median is the average of the middle two numbers: (5+7)/2 = 6.

The product of the average and the median is 7×6=42

Final Answer: Option(E). 42

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