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positive soul
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If ab does not = 0 and a^2*b^2-ab= 6, which of the following 25 Jun 2006, 02:12
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If ab does not = 0 and a^2*b^2-ab= 6, which of the following could be b in terms of a?

I. 1/(2a)
II. -2/a
III. 3/a

A. I only
B. II only
C. I and II
D. I and III
E. II and III.

Please explain your answer.



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If ab does not = 0 and a^2*b^2-ab= 6, which of the following 25 Jun 2006, 02:26
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(ab)^2-ab-6=0
=> (ab-3)(ab+2)=0
=> ab = 3 or ab = -2
=> b = 3/a or b = -2/a

Answer is E.
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dkverma
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If ab does not = 0 and a^2*b^2-ab= 6, which of the following 25 Jun 2006, 06:24
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If ab does not = 0 and a^2*b^2-ab= 6, which of the following could be b in terms of a?

I. 1/(2a)
II. -2/a
III. 3/a

A. I only
B. II only
C. I and II
D. I and III
E. II and III.

Just putting the values in a^2*b^2-ab:

I. a^2*1/4a^2-a/2a = 1/4-1/2 != 6 ----not correct

II. a^2* 4/a^2 -a*(-2/a) = 4 + 2 = 6 --correct

III. a^2*9/a^2 -a*3/a = 9-3 = 6 ---correct

Answer is E.
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If ab does not = 0 and a^2*b^2-ab= 6, which of the following 25 Jun 2006, 06:39
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positive soul
If ab does not = 0 and a^2*b^2-ab= 6, which of the following could be b in terms of a?

I. 1/(2a)
II. -2/a
III. 3/a

A. I only
B. II only
C. I and II
D. I and III
E. II and III.

Please explain your answer.
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factorization of eq "a^2*b^2 - ab = 6" gives the value of b = -2/a and 3/a.

so E. II and III.
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If ab does not = 0 and a^2*b^2-ab= 6, which of the following 25 Jun 2006, 11:44
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yepp E,
two roots of the equation give ab = 3 and ab = -2



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