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25 Jun 2006, 07:08
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What is the probability of getting two cards belonging to two different suits when two cards are drawn at random from a pack of well shuffled cards comprising 52 cards?
a)1/13
b)13/17
c)13/51
d)26/51
e)7/13
how do you figure out that the two cards are drawn one after the other or simultaneously ?
the answers differ based on the assumption one makes.
a)1/13
b)13/17
c)13/51
d)26/51
e)7/13
how do you figure out that the two cards are drawn one after the other or simultaneously ?
the answers differ based on the assumption one makes.
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25 Jun 2006, 07:27
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depends on whether the first is replaced or not. lests suppose the first card is drawan and was not replaced. then now the
P (x =getting two cards from the same suit) = 13/52 x 12/51 = 3/17
P (two cards belonging to two different suits) = 1 - 3/17 = 14/17. but its not the answer.
it is done differently.
P (of getting first card from any suit) = 52/52 = 1
P (of getting second card from any suits other than the first suit) = (51-12) / (51) = 39/51=13/17
So it should be B.
P (x =getting two cards from the same suit) = 13/52 x 12/51 = 3/17
P (two cards belonging to two different suits) = 1 - 3/17 = 14/17. but its not the answer.
it is done differently.
P (of getting first card from any suit) = 52/52 = 1
P (of getting second card from any suits other than the first suit) = (51-12) / (51) = 39/51=13/17
So it should be B.
25 Jun 2006, 07:37
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the prob must be 1-4*13C2/52C2=13/17
Yup. B is the correct answer.
Yup. B is the correct answer.
