Last visit was: 24 Apr 2026, 20:45 It is currently 24 Apr 2026, 20:45
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
User avatar
mahesh004
User avatar
Joined: 10 Oct 2005
Last visit: 13 Mar 2007
Posts: 271
Own Kudos:
609
Location: US
Posts: 271
Kudos: 609
A group of 6 is chosen from 8 men and 5 women so as to 15 Jul 2006, 02:37
Kudos
Add Kudos
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
N
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

History

Date
Time
Result
Not Attempted Yet
A group of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different groups can be formed if two of the men refuse to server together?

a) 3510
b) 2620
c) 1404
d) 700
e) 635



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block below for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
User avatar
BG
User avatar
Joined: 13 Nov 2003
Last visit: 29 Sep 2020
Posts: 352
Own Kudos:
215
Location: BULGARIA
Concentration: INSURANCE, RISK MANAGEMENT
Posts: 352
Kudos: 215
A group of 6 is chosen from 8 men and 5 women so as to 15 Jul 2006, 02:56
Kudos
Add Kudos
Bookmarks
Bookmark this Post
possible combinations 2m 4W and 3M 3W
For Opt1 4 women can be selected in 5 ways, 2 men out of 8 in 28 ways. Remove 1 because of limitation-27 ways.
For opt 1 we have 135 diff groups
Opt2 3 women can be selected in 10 ways, 3 men in 56. Remove 6 because of limitation-50
for opt2 we have 500 diff groups
Then total is 635
User avatar
xsports
User avatar
Joined: 05 Jun 2006
Last visit: 14 Jul 2007
Posts: 52
Own Kudos:
3
Location: London
Posts: 52
Kudos: 3
A group of 6 is chosen from 8 men and 5 women so as to 22 Jul 2006, 03:13
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Sorry, but how did you arrive at 'Remove 6 because of limitation'
User avatar
pravinkawadkar
User avatar
Joined: 14 May 2006
Last visit: 02 Oct 2006
Posts: 24
Own Kudos:
1
Posts: 24
Kudos: 1
A group of 6 is chosen from 8 men and 5 women so as to 22 Jul 2006, 12:59
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Group of 6 with limitation can be formed as
2 M + 4 W or
3 m + 3 W
I forgot total no of men and women. So I am using TM= Total men and TW = Total women

Ans : (TM)C2*(TW)C4 + (TM)C3+(TW)C3

Pravin
User avatar
ps_dahiya
User avatar
Joined: 20 Nov 2005
Last visit: 15 Oct 2019
Posts: 1,486
Own Kudos:
1,238
Concentration: Strategy, Entrepreneurship
Schools:Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Posts: 1,486
Kudos: 1,238
A group of 6 is chosen from 8 men and 5 women so as to 22 Jul 2006, 13:08
Kudos
Add Kudos
Bookmarks
Bookmark this Post
xsports
Sorry, but how did you arrive at 'Remove 6 because of limitation'
Show more


For example if 1 and 2 refuse to work together then cases to be eliminated:

123
124
125
126
127
126
i.e 6 cases.
User avatar
Futuristic
User avatar
Joined: 28 Dec 2005
Last visit: 07 May 2009
Posts: 415
Own Kudos:
52
Posts: 415
Kudos: 52
A group of 6 is chosen from 8 men and 5 women so as to 22 Jul 2006, 16:24
Kudos
Add Kudos
Bookmarks
Bookmark this Post
mahesh004
A group of 6 is chosen from 8 men and 5 women so as to contain at least 2 men and 3 women. How many different groups can be formed if two of the men refuse to server together?

a) 3510
b) 2620
c) 1404
d) 700
e) 635
Show more



E.

We need atleast 2 men and atleast 3 women. Can do this as follows:

1. 2 men + 4 women
2. 3 men + 3 men

For case 1, possibilities =
8C2 X 5C4 = 140
Subtract possibilities where 2 grumpy men are together (2C2 x 6C0) X 5C4 = 5

Case 1: 135

For case 2, poss=
8C3 X 5C3=560
Subtract poss. where 2 grumps are together (2C2 X 6C1) x 5C3 = 60

Case 2: 500

Total = 500 + 135 = 635



Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
Moderator:
Bunuel
Math Expert
109818 posts