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kevincan
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PS: Triangle ACD 17 Jul 2006, 16:15
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PS: Triangle ACD 17 Jul 2006, 20:18
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haas_mba07
Cannot see the point D in the figure??
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agreed but it is there. :wink:

if you extend B and draw a perpendicular line from c to the extended line from B, D is there.

i got C. [sqrt(18) + sqrt(6)]/2.
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PS: Triangle ACD 18 Jul 2006, 10:48
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haas_mba07
Cannot see the point D in the figure??

agreed but it is there. :wink:

if you extend B and draw a perpendicular line from c to the extended line from B, D is there.

i got C. [sqrt(18) + sqrt(6)]/2.
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yup, totally agree! :)

And point D is indeed a hint to solve this problem ..coz you should calculate AB and AC in term of AD ..coz triangle ACD is a 45-90-45 one , triangle BCD is a 30-90-60 one

Also got C as the answer :)
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PS: Triangle ACD 18 Jul 2006, 11:52
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Ok.. I was a bit slow yesterday ... had too much for lunch.. :-)

But yes, got the answer to be sqrt(12)/sqrt(6)-sqrt(2)


which when rationalized gives (sqrt(72)+sqrt(24))/4

Simplifying : (sqrt(18)+sqrt(6))/2

Answer: C
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PS: Triangle ACD 18 Jul 2006, 11:55
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C

Afer getting x, we found that ADC is a right angle triangle with 45-90-45.
So CD = AD let AD = y

Then AC = y * SQRT(2)

Angle BCD = 60. So tan(60) = y/BD i.e BD = a/SQRT(3)

AB = y - y/SQRT(3)

So AC/AB = [y * SQRT(2)]/[y - y/SQRT(3)]

= SQRT(3) * SQRT(2)/[SQRT(3) -1]
= [SQRT(18) + SQRT(6)]/2 i.e C
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PS: Triangle ACD 18 Jul 2006, 14:12
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C it is.

Trigonometry problem :)
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laxieqv
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PS: Triangle ACD 18 Jul 2006, 22:56
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paddyboy
C it is.

Trigonometry problem :)
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Yes, we can solve this problem by the formula of sina, sinb, sinc ..but i think that Kevincan mentioned the point D in order for us to make use of special right triangles :) ...in this sense, he's indeed a great GMAT trainer :king
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PS: Triangle ACD 19 Jul 2006, 04:37
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paddyboy
C it is.

Trigonometry problem :)

Yes, we can solve this problem by the formula of sina, sinb, sinc ..but i think that Kevincan mentioned the point D in order for us to make use of special right triangles :) ...in this sense, he's indeed a great GMAT trainer :king
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I do my best. I appreciate all feedback on the problems I pose, positive or negative. This forum is a great place for all of us to learn!
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MA
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PS: Triangle ACD 19 Jul 2006, 06:52
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kevincan
laxieqv
paddyboy
C it is.

Trigonometry problem :)

Yes, we can solve this problem by the formula of sina, sinb, sinc ..but i think that Kevincan mentioned the point D in order for us to make use of special right triangles :) ...in this sense, he's indeed a great GMAT trainer :king

I do my best. I appreciate all feedback on the problems I pose, positive or negative. This forum is a great place for all of us to learn!
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your questions certainly are great for 800 seekers (though i am not). do you have same type of questions in verbal as well? appreciate your efforts.



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