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haas_mba07
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This question isn't difficult but just takes up time...

If each of the following fractions were written as a repeating decimal, which would have the longest sequence of different digits?

A. 2/11
B. 1/3
C. 41/99
D. 2/3
E 23/37



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koSTARica
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PS: Repeating decimal 01 Aug 2006, 05:57
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haas_mba07
This question isn't difficult but just takes up time...

If each of the following fractions were written as a repeating decimal, which would have the longest sequence of different digits?

A. 2/11
B. 1/3
C. 41/99
D. 2/3
E 23/37
Show more


Firstly, you just exclude 1/3 and 2/3 automatically, 0.3(3) and 0.6(6) respectively;

To calculate A is easy 2/11 = 0.18(18)

41/99 = 0.41(41)

So automatically answer is 23/37!!!


Should do in 2 mins with some concentration!!!
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ps_dahiya
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PS: Repeating decimal 01 Aug 2006, 09:38
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haas_mba07
This question isn't difficult but just takes up time...

If each of the following fractions were written as a repeating decimal, which would have the longest sequence of different digits?

A. 2/11
B. 1/3
C. 41/99
D. 2/3
E 23/37
Show more


E

I did it in less than 30 seconds because from my college days I remember all 1/x upto 4 decimal places for x = 1 to 20.

Eliminate B and D directly.
11 and all multiple of 11s will give only 2 repeating decimals because 1/11 gives 0.090909 and 1/9 = 0.111111....... So B and D has 2 different digits.

All prime numbers greater than 11 give repeating digits after atleast 3 digits.
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haas_mba07
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30 secs!!! What are you... a machine?? :-)

I was trying to work this as fast as I can, but ended up close to 2 mins .. .got it correct, but a little slower than I wanted.


ps_dahiya
haas_mba07
This question isn't difficult but just takes up time...

If each of the following fractions were written as a repeating decimal, which would have the longest sequence of different digits?

A. 2/11
B. 1/3
C. 41/99
D. 2/3
E 23/37

E

I did it in less than 30 seconds because from my college days I remember all 1/x upto 4 decimal places for x = 1 to 20.

Eliminate B and D directly.
11 and all multiple of 11s will give only 2 repeating decimals because 1/11 gives 0.090909 and 1/9 = 0.111111....... So B and D has 2 different digits.

All prime numbers greater than 11 give repeating digits after atleast 3 digits.
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PS: Repeating decimal 01 Aug 2006, 09:52
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A. 2/11 = > 18/99 = 0.18181818....
B. 1/3 => 3/9 = 0.33333333.....
C. 41/99 => 0.41414141.....
D. 2/3 => 6/9 = 0.6666666666...
E 23/37 => 23*27/37*27 = 621/999 = 0.621621621621.....

Thus E.

There's a formular about repeating decimal.. I can't explain..

denominator is 9 => repeating decimal 1
denominator is 99 => repeating decimal 2
denominator is 999 => repeating decimal 3
denominator is 9.....9 => repeating decimal 9.....9

denominator is 90 => repeating decimal 1
denominator is 990 => repeating decimal 2
denominator is 900 => repeating decimal 1
denominator is 999900 => repeating decimal 4

Ex.
0.233312333123331... = 23331/99999
0.2363636... = (236-2)/990
0.2346464646.. = (2346-23)/9900
0.122222... = (12-1)/90
0.222222... = 2/9
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PS: Repeating decimal 02 Aug 2006, 04:37
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E.

Doesnot take much time..... less than 1.5 min....
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PS: Repeating decimal 02 Aug 2006, 21:31
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Agree it takes less than 2 minutes. B and D are straight giveaways.
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pelihu
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PS: Repeating decimal 03 Aug 2006, 00:11
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1-1 1/2 minutes sounds about right. At least with this question, you can be pretty sure that if you take the time you can get the right answer. No tricks, just brute force (except for all you guys that memorized those exponent things).



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Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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