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07 Sep 2020, 08:13
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A dealer owns a group of cars and motorcycles. If the number of tires (excluding spare tires) on the vehicles is 30 more than twice the number of vehicles and the number of cars is 10 more than the number of motorcycle, then the number of cars the dealer owns is
a 10
b 15
c 20
d 30
e none of these
Posted from my mobile device
a 10
b 15
c 20
d 30
e none of these
Posted from my mobile device
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07 Sep 2020, 08:51
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Strange question, because you don't need half of the information it provides. What is the source?
You can answer conceptually - assuming motorcycles have two tires, and cars have four tires, then if all of the vehicles were motorcycles, or if we only counted two tires from each car, the number of tires would be exactly twice the number of vehicles. But we know the number of tires is 30 more than twice the number of vehicles. Those 30 extra tires must come from cars, and since each car has 2 extra tires beyond the two we count when we calculate "twice the number of vehicles", there must be 15 cars.
Or we can answer algebraically. We have m+c vehicles, and 2m + 4c tires. We're then told that 2m + 4c = 2(m + c) + 30. Solving, we get c = 15.
The only reason we'd need to know that there are 10 more cars than motorcycles is if we needed to find the number of motorcycles (there must be 5 of them), but the question doesn't ask about motorcycles, so that information isn't necessary (or even useful) here.
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