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06 Oct 2025, 01:37
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Difficulty:
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68% (01:05) correct
32%
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based on 171
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If \(p = (2^2)(3x)\) and \(r = (2^2)(3y)\), where x and y are prime numbers and x ≠ y, which of the following represents the least common multiple of p and r ?
(A) 12xy
(B) 6xy
(C) xy
(D) 12
(E) 6
(A) 12xy
(B) 6xy
(C) xy
(D) 12
(E) 6
06 Oct 2025, 02:15
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Since 2^2 and 3 is common in both,
LCM will be multiple of 2^2 and 3:
=> 2^2 * 3
=> 4*3
=> 12
Given x and y are prime number so there is nothing in common in x & y:
=> 12 * x * y
=> 12xy
Option A
LCM will be multiple of 2^2 and 3:
=> 2^2 * 3
=> 4*3
=> 12
Given x and y are prime number so there is nothing in common in x & y:
=> 12 * x * y
=> 12xy
Option A
06 Oct 2025, 11:57
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Bunuel
Given that \(p = (2^2)(3x)\) and \(r = (2^2)(3y)\)
p = 4*(3x) = 12x
r = 4*(3y) = 12y
LCM of p and r = common between p and r * terms which are not common
= 12 * x * y
= 12xy.
Option A
