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14 Nov 2006, 16:58
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Hi All,
Here is another question I am stuck at:
Q. Each of the 10 machines works at the same constant rate of doing certain job. The amount of time needed by 10 machines, working together to complete the job is 16 hrs. How many hrs are needed if only 8 machines working together were to complete the job?
a) 18
b) 20
c) 22
d) 24
e) 26
Thanks.
Here is another question I am stuck at:
Q. Each of the 10 machines works at the same constant rate of doing certain job. The amount of time needed by 10 machines, working together to complete the job is 16 hrs. How many hrs are needed if only 8 machines working together were to complete the job?
a) 18
b) 20
c) 22
d) 24
e) 26
Thanks.
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14 Nov 2006, 17:27
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I'm getting 20..
First, we need to find the individual rate of each machine. Since we know the amount of time required for 10 machines is 16, we can create the following equation:
10/x = 1/16.
Solving for x yields 160. Thus the individual rate of each machine is 160.
We can now set up an equation to find out the amount of time required for 8 machines:
8/160 = 1/x
Solve for x: 20
First, we need to find the individual rate of each machine. Since we know the amount of time required for 10 machines is 16, we can create the following equation:
10/x = 1/16.
Solving for x yields 160. Thus the individual rate of each machine is 160.
We can now set up an equation to find out the amount of time required for 8 machines:
8/160 = 1/x
Solve for x: 20
14 Nov 2006, 17:39
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Each machine takes x hours to finish 1 job --> finishes 1/x job in 1 hour
10 machines finishes 1/16 job in 1 hour = 10/x job
1/16 = 10/x
x = 160
So eight machiens finishes 8/x job in 1 hour --> 1/20 job in 1 hour --> 1 job would therefore take 20 hours.
Ans B
10 machines finishes 1/16 job in 1 hour = 10/x job
1/16 = 10/x
x = 160
So eight machiens finishes 8/x job in 1 hour --> 1/20 job in 1 hour --> 1 job would therefore take 20 hours.
Ans B
