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The function f is defined for all positive integrers n by the following rule: f(n) is the number of positive integers each of which is less than n and has no positive factor in common with n other than 1. If p is any prime number then f(p) -
a) p - 1
b) p - 2
c) (p+1)/2
d) (p-1)/2
e) 2
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The function f is defined for all positive integrers n by the following rule: f(n) is the number of positive integers each of which is less than n and has no positive factor in common with n other than 1. If p is any prime number then f(p) -
a) p - 1 b) p - 2 c) (p+1)/2 d) (p-1)/2 e) 2
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A.
Any prime won't have any factor other than itself and 1. So the number should be p-1.
f(11) = 10 (# of integers less than 11 and has no positive factors in common with n other than 1)
f(5) =4 (# of integers less than 5 and has no positive factors in common with n other than 1)
the question says that f(n) is number of positive integers less than n that have factors in common ....
so, when considering the primes, which have just itself and 1 as a factor, shouldnt the answer really be p-2, because we cannot count p ... right ?
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I agree, actually, according to my calculations ALL the answer choices are correct, cuz there are no restrictions on the number of the intengers other than each must be less than p and have only one common divisor 1.
The function f is defined for all positive integrers n by the following rule: f(n) is the number of positive integers each of which is less than n and has no positive factor in common with n other than 1. If p is any prime number then f(p) -
a) p - 1 b) p - 2 c) (p+1)/2 d) (p-1)/2 e) 2
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pmenon
the question says that f(n) is number of positive integers less than n that have factors in common ....
so, when considering the primes, which have just itself and 1 as a factor, shouldnt the answer really be p-2, because we cannot count p ... right ?
Show more
I agree, actually, according to my calculations ALL the answer choices are correct, cuz there are no restrictions on the number of the intengers other than each must be less than p and have only one common divisor 1.
f.e: try p= 7
then,
f(7) can be
A) 1,2,3,4,5,6
B) 1,2,3,4,5
C) 1,2,3,4
D) 1,2,3
E) 1
all satisfy the conditions, correct me please if I miss something
what is OA anyways?
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.