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jp888
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the question says that f(n) is number of positive integers less than n that have factors in common ....

so, when considering the primes, which have just itself and 1 as a factor, shouldnt the answer really be p-2, because we cannot count p ... right ?
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pmenon
the question says that f(n) is number of positive integers less than n that have factors in common ....

so, when considering the primes, which have just itself and 1 as a factor, shouldnt the answer really be p-2, because we cannot count p ... right ?


I agree, actually, according to my calculations ALL the answer choices are correct, cuz there are no restrictions on the number of the intengers other than each must be less than p and have only one common divisor 1.
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jp888
The function f is defined for all positive integrers n by the following rule: f(n) is the number of positive integers each of which is less than n and has no positive factor in common with n other than 1. If p is any prime number then f(p) -

a) p - 1
b) p - 2
c) (p+1)/2
d) (p-1)/2
e) 2

pmenon
the question says that f(n) is number of positive integers less than n that have factors in common ....

so, when considering the primes, which have just itself and 1 as a factor, shouldnt the answer really be p-2, because we cannot count p ... right ?


I agree, actually, according to my calculations ALL the answer choices are correct, cuz there are no restrictions on the number of the intengers other than each must be less than p and have only one common divisor 1.

f.e: try p= 7

then,

f(7) can be

A) 1,2,3,4,5,6
B) 1,2,3,4,5
C) 1,2,3,4
D) 1,2,3
E) 1

all satisfy the conditions, correct me please if I miss something

what is OA anyways?



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