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06 Sep 2022, 03:58
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (01:16) correct
27%
(01:41)
wrong
based on 261
sessions
History
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Time
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Not Attempted Yet
Five marbles are in a bag: two are red and three are blue. If Andy randomly picks two of the marbles, what is the probability that at least one of the marbles he chooses will be red?
A. 2/5
B. 6/10
C. 7/10
D. 15/20
E. 19/20
A. 2/5
B. 6/10
C. 7/10
D. 15/20
E. 19/20
07 Sep 2022, 12:47
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Bunuel
Total possible options (Picking 2 marbles from a total of 5 marbles) = \(5c2 = 10\)
We need to find P(At least 1 red marble) = 1 - P(No red marble)
P(No red marble) = P(Both blue marbles) or picking 2 blue marbles from a possible 3 blue marbles = \(\frac{3c2}{10} = \frac{3}{10}\)
P (At least 1 red marble) = \(1 - \frac{3}{10} = \frac{7}{10}\)
Answer - C
07 Sep 2022, 13:55
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Let's consider the event A=not picking any red marble and B= picking blue marbel
P(A) =1- P(B)
P(B)=3c2/5c2 =>P(B)=3/10
then P(A) = 1-3/10 =7/10
C is the winner
P(A) =1- P(B)
P(B)=3c2/5c2 =>P(B)=3/10
then P(A) = 1-3/10 =7/10
C is the winner
