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delwar2
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maliyeci
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delwar2
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Yes NM = 2 pi. ON = 3,5 pi, NM= 2pi and MR=3,5 pi. Total makes 9pi. Half the circle. Angle of ON = 70, NM=40, MR=70. I confused the chords.
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delwar2
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Could you please explain how you got those angles???

thanks,

tariq
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aknine
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I would agree with A i.e. 2 pi

Please view the attachment to understand better.
Given R= 9
circumference= 2 pi R

angle NRO= 35degree, therefore, angle subtended at the center angle NXO= 70 degree.

18 pi / 360 degrees = ON / 70 degrees (this would give the length of the arc ON). On solving we get ON= 7 pi/2.

Now, ON= MR= 7 pi/2, because NM is parallel to OR.
We need to find arc NM= arc OR-arc ON-arc MR= 9pi-7pi= 2pi
Attachments

circle problem.jpg
circle problem.jpg [ 15.36 KiB | Viewed 1502 times ]

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maliyeci
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delwar2
Could you please explain how you got those angles???

thanks,

tariq
This graphic exactly shows everything. It is given that, ORN=35 degrees. So the angle of chord that this angle sees is 70 degrees. Because of parallelism, the theoretic angle MOR = 35 degrees too. So the angle of chord that this angle sees is 70 degrees too. Since a half circle is 180 degrees. You can see that MN will be 180-70-70=40 degrees. It means the length of that chord will be 40/360=1/9 of circle. Circumference of circle is 18pi so the length of chord is 2 pi.



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