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14 Jul 2009, 14:09
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The x-intercept of a line passing through points (5,-2) and (6,9) is _________________________
please explain.
57/11
please explain.
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14 Jul 2009, 14:16
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You have to use a system of 2 equations. Plug in your given points into the formula for a line: y=mx+b
A: -2=m(5)+b
B: 9=m(6)+b
Subtract the bottom from the top:
-11 = -m
m = 11
Plug back into a to find the full equation:
A: -2=11(5)+b
b=-57
x-int. is where the line crosses the x-axis which means y=0. Plug this in:
y=11x-57
0=11x-57
x=57/11
A: -2=m(5)+b
B: 9=m(6)+b
Subtract the bottom from the top:
-11 = -m
m = 11
Plug back into a to find the full equation:
A: -2=11(5)+b
b=-57
x-int. is where the line crosses the x-axis which means y=0. Plug this in:
y=11x-57
0=11x-57
x=57/11
15 Jul 2009, 08:07
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given 2 points there is a direct eqn for a line
\(y-y2 = y2-y1/x2-x1 (x-x1)\)
using this , you get the eqn y+2 = 11(x-5)
for x-interecept you put y=0 and you get x = 57/11
\(y-y2 = y2-y1/x2-x1 (x-x1)\)
using this , you get the eqn y+2 = 11(x-5)
for x-interecept you put y=0 and you get x = 57/11
