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29 Sep 2009, 06:55
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If a triangle in the xy-coordinate system has vertices at
(-2 , -3), (4, -3) and (28, 7), what is the area of the triangle?
30
36
48
60
65
(-2 , -3), (4, -3) and (28, 7), what is the area of the triangle?
30
36
48
60
65
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29 Sep 2009, 07:24
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ANS = 30.
Think of (-2,-3) and (4,-3) as the base with length 6, since they are the same y-coordinates.
The height of the triangle is basically 7 (from 28,7) + 3 (from 4,-3) = 10.
Area = 1/2 B H = (1/2)*10*6 = 30
Think of (-2,-3) and (4,-3) as the base with length 6, since they are the same y-coordinates.
The height of the triangle is basically 7 (from 28,7) + 3 (from 4,-3) = 10.
Area = 1/2 B H = (1/2)*10*6 = 30
29 Sep 2009, 07:26
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Solution is in the figure
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adsız.JPG [ 10.36 KiB | Viewed 1380 times ]
