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22 Nov 2009, 19:54
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22 Nov 2009, 20:34
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Two equations can be formed from the question stem
1---- (a+2x)^2-a^2=132 => 4 x^2+4 a x132
2-----a=x+5
where a= width of the patio
x= width of the walk way
Solving we get a=8 and x=3
So the area of patio is 64
Hence the answer should be B
1---- (a+2x)^2-a^2=132 => 4 x^2+4 a x132
2-----a=x+5
where a= width of the patio
x= width of the walk way
Solving we get a=8 and x=3
So the area of patio is 64
Hence the answer should be B
22 Nov 2009, 20:45
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Area of patio & walkway together = area of walkway + area of patio
\((3x+5)^2 = 132 + (x+5)^2\)
\((3x+5)^2 - (x+5)^2 = 132\)
\(8x^2+20x=132\)
\(x(2x+5) = 33 = 3*11\)
so \(x=3\)
area of patio is \((x+5)^2= 8^2 = 64\)
Answer B
\((3x+5)^2 = 132 + (x+5)^2\)
\((3x+5)^2 - (x+5)^2 = 132\)
\(8x^2+20x=132\)
\(x(2x+5) = 33 = 3*11\)
so \(x=3\)
area of patio is \((x+5)^2= 8^2 = 64\)
Answer B
